Question

Suppose f'(7)=9 and g(7)= 5. Find h'(7) where h(x) = 3f(x) + 2g(x) + 7 h'(7)=???

Answer 1

Answer:

The value of h'(7) = 44 .

Step-by-step explanation:

Given:

f'(7)=9 and g(7)= 5

We have to find : h'(7)

Also,

⇔ $h(x) = 3f(x) + 2g(x) + 7$   ...equation (i)

Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:

⇔ $h(7) = 3f(7) + 2g(7) + 7$

⇔ $h(7) = 3f(7) + 2g(7) + 7$

Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:

⇔ $h(7) = 3(9) + 2(5) + 7$

⇔ $h(7)=27+10+7$

⇔ $h(7)=44$

So the value of h=(7) = 44 .