Suppose f'(7)=9 and g(7)= 5. Find h'(7) where h(x) = 3f(x) + 2g(x) + 7 h'(7)=???
1 answer:
Answer:
The value of h'(7) = 44 .
Step-by-step explanation:
Given:
f'(7)=9 and g(7)= 5
We have to find : h'(7)
Also,
⇔ ...equation (i)
Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:
⇔
⇔
Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:
⇔
⇔
⇔
So the value of h=(7) = 44 .
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Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
( ) & (
)-
y - =
( x -
)
i.e. <em> y - 7= ( x- 1)</em>
<em> y - 7 = ( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.