The answer is 904.78cm³ Hope I helped, please rate brainliest.
Answer:
A = 57°
B = 19°
C = 104°
Step-by-step explanation:
We have a triangle with 3 angles:
A, B, and C.
We know that:
"Angle A is 3 times larger than angle B"
We can write this as:
A = 3*B
"Angle C was 10° less than 6 times angle B"
This can be written as:
C = 6*B - 10°
And we also know that the sum of all interior angles of a triangle is 180°
Then we also have the equation:
A + B + C = 180°
So we have a system of 3 equations:
A = 3*B
C = 6*B - 10°
A + B + C = 180°
To solve this, the first step is to isolate one of the variables in one of the equations.
We can see that A is already isolated in the first one, so we can skip that step.
Now we need to replace A in the other equations, to get:
C = 6*B - 10°
(3*B) + B + C = 180°
Now we have a system of two equations.
Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:
3*B + B + (6*B - 10°) = 180°
Now we can solve this for angle B
4*B + 6*B - 10° = 180°
10*B - 10° = 180°
10*B = 180° + 10° = 190°
B = 190°/10 = 19°
Now that we know the measure of angle B, we can input this in the equations:
A = 3*B
C = 6*B - 10°
To find the measures of the other two angles:
A = 3*19° = 57°
C = 6*19° - 10° = 104°
Answer:
x=30o+n90on∈Z
Step-by-step explanation:
cos2x=sin(90o−2x)=sin(2x−30o)
Which mean 90o−2x=2x−30o+n360o
or 90o−2x+2x−30o=(2n+1)180o
The later cannot be true.
so x=30o+n90on∈Z
1) factor to see if you can get anything to cancel out before you multiply
2) the rest of my work is shown in the picture attached
3) the answer is n^2
This is a geometric sequence with first term 1 and common ratio -1/2. r=-1/2.
a(n) = a(1)*(r)^(n-1).
Check: If n=2 our formula must return -1/2. Does it?
a(2) = 1(-1/2)^(2-1) = (-1/2)^1 = - 1/2. Yes.
a(3) should be 1/4. Is it? a(3) = (-1/2)^(3-1) = 1/4 Yes.
Then a(8) = (-1/2)^(8-1) = (-1/2)^7 = -1 / 2^7 = -1/128 (answer)
