Answer:
Explanation:
Given the parallex of the star is 0.1 sec.
The distance is inversely related with the parallex of the star. Mathematically,
Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.
Now,
And also know that,
Therefore the distance of the star is away.
d = distance between the two point charges = 60 cm = 0.60 m
r = distance of the location of point "a" where the electric field is zero from charge between the two charges.
= magnitude of charge on one charge
= magnitude of charge on other charge
= 3
= Electric field by charge
at point "a"
= Electric field by charge
at point "a"
Electric field by charge at point "a" is given as
= k
/r²
Electric field by charge at point "a" is given as
= k
/(d-r)²
For the electric field to be zero at point "a"
=
k /(d-r)² = k
/r²
/(d-r)² = 3
/r²
1/(0.60 - r)² = 3 /r²
r = 0.38 m
r = 38 cm
We have centripetal acceleration =
So, v =
Now by equation of motion we have S= ut +0.5a
S =displacement, u = initial velocity, a= acceleration and t = time
Here S = 2r and a = g , u = 0
Distance traveled in horizontal direction =