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MakcuM [25]
2 years ago
14

What is the distance to a star whose parallex is 0.1 sec?

Physics
1 answer:
Arte-miy333 [17]2 years ago
6 0

Answer:

30.86\times 10^{13} km

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

d=\frac{1}{P}

Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

d=\frac{1}{0.1}\\d=10 parsec

And also know that,

1 parsec=3.086\times 10^{13} km

Therefore the distance of the star  is 30.86\times 10^{13} km away.

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3 years ago
Copper wire of diameter 0.289 cm is used to connect a set of appliances at 120 V, which draw 1850 W of power total. The resistiv
vodka [1.7K]

Answer:

(a) The power wasted for 0.289 cm wire diameter is 15.93 W

(b) The power wasted for 0.417 cm wire diameter is 7.61 W

Explanation:

Given;

diameter of the wire, d = 0.289 cm = 0.00289 m

voltage of the wire, V = 120 V

Power drawn, P = 1850 W

The resistivity of the wire, ρ = 1.68 x 10⁻⁸ Ω⋅m

Area of the wire;

A = πd²/4

A = (π x 0.00289²) / 4

A = 6.561 x 10⁻⁶ m²

(a) At 26 m of this wire, the resistance of the is

R = ρL / A

R = (1.68 x 10⁻⁸  x 26) / 6.561 x 10⁻⁶

R = 0.067 Ω

Current in the wire is calculated as;

P = IV

I = P / V

I = 1850 / 120

I = 15.417 A

Power wasted = I²R

Power wasted = (15.417²)(0.067)

Power wasted = 15.93 W

(b) when a diameter of 0.417 cm is used instead;

d = 0.417 cm = 0.00417 m

A = πd²/4

A = (π x 0.00417²) / 4

A = 1.366 x 10⁻⁵ m²

Resistance of the wire at 26 m length of wire and  1.366 x 10⁻⁵ m² area;

R = ρL / A

R = (1.68 x 10⁻⁸  x 26) / 1.366 x 10⁻⁵

R = 0.032 Ω

Power wasted = I²R

Power wasted = (15.417²)(0.032)

Power wasted = 7.61 W

5 0
3 years ago
Thank you if you them
astraxan [27]

Answer:

Explanation:

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5. You would get shocked in a bumper car by touching the floor and the ceiling at the same time. This means you are completing the circuit allowing electricity to flow.

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8. Materials that allow electrons to move easily from atom to atom are called conductors.

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4 0
2 years ago
How much mass dose a vehicle have if it needs 29000 Newton’s of force to accelerate it at a rate of 4m/s
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F=ma
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