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MakcuM [25]
3 years ago
14

What is the distance to a star whose parallex is 0.1 sec?

Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

30.86\times 10^{13} km

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

d=\frac{1}{P}

Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

d=\frac{1}{0.1}\\d=10 parsec

And also know that,

1 parsec=3.086\times 10^{13} km

Therefore the distance of the star  is 30.86\times 10^{13} km away.

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A container has a large cylindrical lower part with a long thin cylindrical neck open at the top. The lower part of the containe
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Answer:

8.6*10^5N

Explanation:

Pressure of the water = density of water * height of the water * acceleration due to gravity

Pressure of water = 1000*9.81*(2.5 + 8.50)

Pressure of the water = 107910 = 1.08*10^5

And Pressure = force / A

Force = Pressure * A(surface area of the container)

Force = 1.08*10^5 * 8 = 863280 = 8.6*10^5N

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3 years ago
Which of the following statements is true?
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Answer:

Concrete absorbs visible light and re-radiates it as infrared energy.

Explanation:

As we know that concrete will not reflect 100% light incident on it but it will absorb few energy and remaining energy is reflected back.

So here when visible light incident on the concrete then few of its energy is absorbed by is and then the remaining energy is reflected back.

Since the reflected energy must be less than the energy which incident on the concrete so here we will say that the reflected waves must be of less frequency range

so here most appropriate energy range of reflected wave is infrared waves

so here correct answer will be

Concrete absorbs visible light and re-radiates it as infrared energy.

6 0
3 years ago
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Complete the table
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Explanation:

4 0
3 years ago
if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds​
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Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

{ \boxed{ \tt{s = ut +  \frac{1}{2} {gt}^{2}  }}}

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{ \tt{0.8 = (0 \times t) + ( \frac{1}{2}  \times 10 \times  {t}^{2} )}} \\  \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t =  \sqrt{0.16} }} \\  \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \:  \: }}}}

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The weight of the sky diver contributes to the force pushing him down.

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