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Paraphin [41]
3 years ago
14

Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu

de of q2 . At which point a on the axis is the electric field zero?
Physics
1 answer:
Alex777 [14]3 years ago
8 0

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge q_{1} between the two charges.

q_{1} = magnitude of charge on one charge

q_{2} = magnitude of charge on other charge

q_{1} = 3 q_{2}

E_{1} = Electric field by charge q_{1} at point "a"

E_{2} = Electric field by charge q_{2} at point "a"


Electric field by charge q_{1} at point "a" is given as

E_{1} = kq_{1} /r²

Electric field by charge q_{2} at point "a" is given as

E_{2} = kq_{2} /(d-r)²

For the electric field to be zero at point "a"

E_{2} = E_{1}

kq_{2} /(d-r)² = kq_{1} /r²

q_{2} /(d-r)² = 3q_{2} /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm


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