What force is necessary to keep a mass of 0.8 kg revolving in a horizontal circle of radius 0.7 m with a period of 0.5 s? What i
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Answer:
The work done by the child as the tricycle travels down the incline is 416.96 J
Explanation:
Given;
initial velocity of the child, = 1.4 m/s
final velocity of the child, = 6.5 m/s
initial height of the inclined plane, h = 2.25 m
length of the inclined plane, L = 12.4 m
total mass, m = 48 kg
frictional force, = 41 N
The work done by the child is calculated as;
Therefore, the work done by the child as the tricycle travels down the incline is 416.96 J
The similarities and the differences between gravitational and electric force are listed below
Explanation:
- The magnitude of the gravitational force between two objects is given by Newton's law of gravitation:
where
is the gravitational constant
are the masses of the two objects
r is the separation between them
- Coloumb's law gives instead the strength of the electrostatic force between two charged objects, which is
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
By comparing the two equations, we find the following similarities:
- Both the forces are inversely proportional to the square of the distance between the two objects,
- Both the forces are proportional to the product between the "main quantity" of each force, which is the mass for the gravitational force (
) and the charge for the electric force (
Instead, we have the following differences:
- The gravitational force is always attractive, since the sign of
is always positive, while the electric force can be either attractive or repulsive, since the sign of
can be either positive or negative
- The value of the gravitational costant G is much smaller than the value of the Coulomb's constant, so the gravitational force is much weaker than the electric force
Learn more about gravitational force and electric force:
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