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Mathematics

1 answer:

Julli [10]3 years ago

3 0

The answers are:

B - Minimum Payment
B - Finance Charge

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What is the value of H? Help ASAP!

tamaranim1 [39]

8 times square root of 2

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3 years ago

What is the length of the diagonal if a 10 cm by 15cm rectangle ?

mojhsa [17]

In other words, if a rectangle is 10 cm by 15 cm, what is the length of the diagonal? Use the Pythagorean Theorem. a^2+b^2=c^2, where c is the measure of the hypotenuse.

4 0

4 years ago

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The speed of a stream is 4 mph a boat travels 3 miles upstream in the same time it takes to travel 11 miles downstream what is t

vazorg [7]

$\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&3&r-4&t\\
downstrea&11&r+4&t
\end{array}\\\\\\ recall\implies d=rt\\\\
-----------------------------\\\\

\begin{cases}
3=(r-4)(t)
\\\\
11=(r+4)(t)\\
--------------\\
3=(r-4)(t)\to \frac{3}{r-4}=\boxed{t}\qquad thus
\\\\
11=(r+4)(t)\to 11=(r+4)\left( \boxed{\frac{3}{r-4}}\right)
\end{cases}$

solve for "r"

6 0

3 years ago

Peanuts are sold in 8-ounce and 12-ounce packages.

allsm [11]

Answer:

C) 24

Step-by-step explanation:

8; 16 24 32 40 48

12; 24 36 48 69 72

They both have the common multiple of 24 and 48 in the intermediate multiplication since 24 is half of 48 and is the smallest multiple that is the answer.

6 0

2 years ago

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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$