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AnnyKZ [126]
3 years ago
9

If the perimeter of the bedroom is 42 feet and the length what is the width of the bedroom

Mathematics
1 answer:
Citrus2011 [14]3 years ago
6 0
The answer to the question is 42ft.
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Need help please thanks you
Nataly [62]
A + C = 90/190

B + D = 100/190

Therefore answer is H
4 0
2 years ago
What are the factors of the square root of 329
Andru [333]

Answer: x=-\dfrac{3}{2}, 7

Step-by-step explanation:

2x^2-10x-26=x-5

2x^2-10x-26-x+5=0  Move all terms to one side

2x^2-11x-21=0 Simplify 2{x}^{2}-10x-26-x+5

2x^2+3x-14x-21=0 Split the second term

x(2x+3)-7(2x+3)=0  Factor out common terms in the first two terms, then in the last two terms.

(2x+3)(x-7)=0 Factor out the common term 2x+3

x=-\dfrac{3}{2}, 7

5 0
2 years ago
Read 2 more answers
12^3 tanx-4^3tan2x<br>solve next step fast guys​
shepuryov [24]

Step-by-step explanation:

3 tan 2x - 4 tan 3x = tan² 3x * tan 2x

3 (tan 2x - tan 3x) = tan 3x + tan² 3x * tan 2x

= tan 3x (1 + tan 3x * tan 2x)

3 (tan 2x - tan 3x)/(1 + tan 3x * tan 2x) = tan 3x

3 * (- tan x) = tan 3x

-3tanx = (3 tan x - tan³ x) / (1 - 3 tan² x)

3 - tan² x = - 3 + 9 tan² x

tan x = + √3 /√5 or - √3/√5

4 0
3 years ago
Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3
Whitepunk [10]

If f(x)=4x-3:

\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4

If f(x)=4x^{-3}:

\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}

\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}

\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}

7 0
3 years ago
What's the answer for 0.63
aleksandr82 [10.1K]
What answer are you looking for percents,fraction form, etc ?
6 0
3 years ago
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