It looks like you want to compute the double integral

over the region <em>D</em> with the unit circle <em>x</em> ² + <em>y</em> ² = 1 as its boundary.
Convert to polar coordinates, in which <em>D</em> is given by the set
<em>D</em> = {(<em>r</em>, <em>θ</em>) : 0 ≤ <em>r</em> ≤ 1 and 0 ≤ <em>θ</em> ≤ 2<em>π</em>}
and
<em>x</em> = <em>r</em> cos(<em>θ</em>)
<em>y</em> = <em>r</em> sin(<em>θ</em>)
d<em>x</em> d<em>y</em> = <em>r</em> d<em>r</em> d<em>θ</em>
Then the integral is

New volume is given by:
New volume=(old volume)×(4×2/9×2/9)
simplifying the above we get:
New volume=(old volume)×16/81
Thus the new volume is 16/81 times the old volume
old volume=πr²h
Hence:
Answer:16/81πr²h
Answer:

Step-by-step explanation:
The first step is to find the GCF. Here, it's 3.

Then, you factor the polynomial in the parenthesis.
To find the factors, you will need to find 2 numbers that add to -7, and multiply to 10. -2 and -5 add to -7 and multiply to 10. Now, replace -7a with the factors.

This of this polynomial as 2 problems.

Then, factor again.


Then, you keep the factors in parenthesis, and combine the numbers on the outside.

Since, there are 2 of the same factor, you only need one.

BUT REMEMBER!! In the very beginning, we had a 3 that we took out, we STILL need to add that to the final answer. The <u>final answer</u> is:

Answer:
use trig
Step-by-step explanation:
sin(15) = 100/x
x = 100/sin(15)
use calculator