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3 years ago

In which direction will this parabola open? x=53(y+17)^2-41

1 answer:

8 0

$x=53(y+17)^2-41\\
x=53(y^2+34y+289)-41\\
x=53y^2+1802y+15317-41\\
x=53y^2+1802y+15276$

As a>0 so the concavity (open) of the parable is to the right.

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nalin [4]

Answer:

The coordinates of endpoint V is (7,-27)

Solution:

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is $\frac{x_{1}+x_{2}}{2}$ , $\frac{y_{1}+y_{2}}{2}$

As per the formula, $\frac{x_{1}+x_{2}}{2}$ =5, $\frac{y_{1}+y_{2}}{2}$ =-11

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Substituting the value of $x_{1}$ we get,

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