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3 years ago

Filled with jelly beans. If the jar has a 15% are purple How many purple beans are they ?

Mathematics

1 answer:

Rzqust [24]3 years ago

8 0

Answer:

147 purple jelly beans

Step-by-step explanation:

15% of 980 is 147

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Simplify by dividing 3/5 ÷ -4/9 1. -27/20 2. 27/20 3. -12/45 4. 12/45

kramer

Answer:

The answer to your question is -27/20

Step-by-step explanation:

Divide 3/5 ÷ - 4/9

Process

1.- Just multiply the numerator of the first fraction by the denominator of the second fraction.

3 x - 9 = -27

2.- Multiply the denominator of the first fraction by the numerator of the second fraction.

5 x 4 = 20

3.- Join both results

-27/20

5 0

3 years ago

- vnuәуре отти аропс

Daniel [21]

equation in slope-intercept form is:

$y=9x+7$

Step-by-step explanation:

The general form of slope-intercept form is:

$y=mx+b$

where m is the slope and b is the y-intercept

In the question we are given slope m=9 and a point(0,7)

We will find b i.e y-intercept

$y=mx+b\\7=9(0)+b\\7=0+b\\b=7$

So, value of b=7 and value of slope m=9

So, equation in slope-intercept form is:

$y=9x+7$

Keywords: slope-intercept form

Learn more about slope-intercept form at:

#learnwithBrainly

8 0

3 years ago

Wendy borrowed a 370-page book from the library. She has already read 20 pages. The book is due back to the library in 7 days. W

Leviafan [203]

Answer:

n ≥ 50

Step-by-step explanation:

Total pages = 370

Read pages = 20

Number of days remaining = 7

Reading rate per day = n

7n + 20 ≥ 370

7n ≥ 370 - 20

7n ≥ 350

n ≥ 350/7

n ≥ 50 pages per day for the remaining 7 days

5 0

3 years ago

How many students are in Year 11?

worty [1.4K]

Answer:

308

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A coin is tossed 600times with the frequencies as:

brilliants [131]

Answer:

see below

Step-by-step explanation:

Total number of trials =600.

Number of heads = 342.

Number of tails = 258

On tossing a coin,

$let \: E_1 \: and \: E_2 \: be \: the \: events \: of \: getting \: a \: head$

and of getting a tail respectively.

then,

$1) \: P \: (getting \: a \: head) = \: P \: (E_1)$

$\longrightarrow \: \frac{number \: of \: heads \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{342}{600} = \frac{57}{100}$

$\longrightarrow \: 0.57$

$\red{ \rule{150pt}{3pt}} \:$

$2) P (getting \: a\: tail) =P (E_2)$

$\longrightarrow \: \frac{number \: of \: tails \: coming \: up}{total \: number \: of \: trials}$

$\longrightarrow \: \frac{258}{600} = \frac{43}{100}$

$\longrightarrow \: 0.43$

6 0

3 years ago