Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
<h3>What is the distance?</h3>
Distance is the movement of an object regardless of direction. The distance can be defined as the amount of length an object has covered, regardless of its starting or ending position
We know that r × t = d
r = rate of speed
t = time
d = distance
For the motor boat
9 × t = d = rate × time
For the tour boat
27 × (t - 2) = d = rate × time
When they both cover the same distance in the same amount of time, they will eventually cross paths.
They both cover the same d-mile distance, so:
9 ×t = 27 × (t - 2)
Simplify to get:
9 × t = 27 × t - 54
18 t = 54
t = 3
The motor boat will have traveled at 9 mph for 3 hours to make a distance of 9 × 3 = 27 miles.
The tour boat will have traveled at 27 mph for 1 hour to make a distance of 1 × 27 = 27 miles.
Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
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Answer:
A. 7
Step-by-step explanation:
Since the triangle sides are not defined, therefore let the base side have the 12 unit and one of the slant side be 7 unit.
Therefore height of the triangle, h can gotten from the Pythagoras theorem as thus:
7² = (12/2)² + h²
49 = 36 + h²
h² = 49 - 36 = 13
h = √13
knowing the height of the triangle, we can apply same rule to the other unknown slant side, x as thus:
x² = (12/2)² + h²
x² = 36 + 13 = 49
x = √49
x = 7
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
Answer: X does not intercept (none)
Y=(0,5)
Step-by-step explanation:
