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Over [174]
3 years ago
8

4=2/4u one step equation

Mathematics
1 answer:
docker41 [41]3 years ago
3 0
4 = 2/4u

Multiply both sides by 4u

16u = 2

Divide both sides by 16, and simplify.

u = 1/8
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The ratio of girls to boys who participated in the quiz bowl was 7:5. There were 42 girls in the competition. How many boys part
Vlad1618 [11]
7*6=42 girls
5*6=30 boys
7:5=42:30
30 boys participated
4 0
3 years ago
Read 2 more answers
If Saturn's mass is 5.685 · 10^26 kilograms and Mercury's is 3.302 · 10^23 kilograms
marusya05 [52]
Do the division
(5.685 * 10^26) / (3.302*10^23)

=  1.722 * 10^3

or 1722 times greater
8 0
3 years ago
The percentage of cotton in material used to manufacture men's shirts follows.
velikii [3]

Answer:

Median = 34.55

Quartiles:

Q1 = 33.1

Q2 = 34.55

Q3 = 35.6

Inter Quartile range = 2.5

Step-by-step explanation:

Step 1

We arrange the given the following data from lowest to the highest

32.0, 32.1, 32.1, 32.2, 32.4, 32.5, 32.5, 32.5, 32.8, 32.8, 32.8, 32.8, 32.9, 32.9, 33.0, 33.0, 33.2, 33.2, 33.2, 33.2, 33.5, 33.6, 33.8, 33.8, 33.9, 34.0, 34.0, 34.1, 34.1, 34.3, 34.4, 34.5, 34.6, 34.6, 34.6, 34.7, 34.7, 35.0, 35.0, 35.1, 35.1, 35.2, 35.4, 35.5, 35.5, 35.5, 35.5, 35.6, 35.6, 36.1, 36.3, 36.4, 36.4, 36.4, 36.5, 36.6, 36.7, 36.7, 37.0, 37.1, 37.4, 37.4, 37.6, 37.8

a. Construct a stem-and-leaf display for the data.

Stem and leaf Display

Stem | Leaf

32 | 0,1,1,2,4,5,5,5,8,8,8,8,9,9

33 | 0,0,2,2,2,2,5,6,8,8,9

34 | 0,0,1,1,3,4,5,6,6,6,7,7

35 | 0,0,1,1,2,4,5,5,5,5,6,6,

36 | 1,3,4,4,4,5,6,7,7,

37 | 0,1,4,4,6,8

b. Calculate the median and quartiles of these data.

Number of terms = 64

1) Median = 1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

2) First Quartile

1/4(n + 1)th value

n = 64

= 1/4(64 + 1)th

= 1/4(65)th

= 16.5th value

This means it is between the 16th and 17th value

16th value = 33.0

17tj value = 33.2

= 33.0 + 33.2/2

= 66.2/2

= 34.55

Q1 --> 33.1

3)Second Quartile = Median

1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

Q2 --> 34.55

Third Quartile

3/4(n + 1)th value

n = 64

= 3/4(64 + 1)th

= 3/4(65)th

= 48.75 th value

This means it is towards the 49th value

32nd = 34.5

Hence,

Q3 --> 35.6

Inter Quartile range

Q3 - Q1

= 35.6 - 33.1

= 2.5

8 0
3 years ago
Pls help me need help
Rashid [163]

Answer:1,4/5

Step-by-step explanation:https://www.cymath.com/answer?q=5x%5E2%2Bx%3D4

5 0
3 years ago
Write and graph a system of inequalities that models the situation.
liubo4ka [24]

Answer:

The feasible region in the attached figure

Step-by-step explanation:

Let

x ----> the number of shirts

y ----> the number of pants

we know that

The cost of the shirts (number of shirts multiplied by the cost of one shirt) plus the cost of the pants (number of pants multiplied by the cost of one pant) must be less than or equal to $80

so

The inequality that represent this problem is

5x+8y\leq 80

using a graphing tool

The feasible region is the triangular shaded area

see the attached figure

7 0
4 years ago
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