At standard temperature and pressure, the volume of 58 gms of chlorine gas is 7.08 L.
<h3>What is STP?</h3>
STP is the condition of the ideal gas that relates to the moles, pressure, temperature, and volume. The ideal gas law at the STP is given as:
PV = nRT
Given at STP,
Pressure (P) = 1 atm
Temperature (T) = 273 K
Gas constant (R) = 0.0821 L atm/ mol K
Moles (n) of chlorine gas is calculated as:
Moles = Mass / Molar mass
n = 58.0 / 70.90
= 0.818 moles
The volume for the ideal gas equation is calculated as:
V = n * R * T / P
V = 7.08 / 1
V = 7.08 L
Therefore, at STP the volume of the gas is 7.08 L.
Learn more about STP here:
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Answer:
0.00915 M of 
remain after 5.16 seconds.
Explanation:
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Given that:
The rate constant, k = 
s⁻¹
Initial concentration = 0.054 M
Final concentration = ? M
Time = 5.16 s
Applying in the above equation, we get that:-
![[A_t]=0.054e^{-0.344\times 5.16}\ M=\frac{1\times \:0.054}{e^{1.77504}}\ M=0.00915\ M](https://tex.z-dn.net/?f=%5BA_t%5D%3D0.054e%5E%7B-0.344%5Ctimes%205.16%7D%5C%20M%3D%5Cfrac%7B1%5Ctimes%20%5C%3A0.054%7D%7Be%5E%7B1.77504%7D%7D%5C%20M%3D0.00915%5C%20M)
<u>0.00915 M of remain after 5.16 seconds.</u>
Answer:
Electrons get farther from the nucleus.
Explanation:
By going from the top to the bottom of a group, the atomic number increases. That would mean that:
- The number of orbitals increases, as there are more electrons.
- A higher atomic number implies an increasing number of neutrons.
- As there are more electrons, they get farther from the nucleus. The farther an electron is from the nucleus, the easier it is for the electron to be removed from the atom.
We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH- = 10^-10.75 equal to B. 1.778 x 10^-11 M
