Answer:
0.1 mol
Explanation:
Number of mole= mass/molar mass
lithium have a mass number of 7 and oxygen have a mass number of 16.
so, (7x2) + 16
= 30
therefore, number of moles = 2.93/30
= 0.10
Answer : The current passing between the electrodes is, 
Explanation :
First we have to calculate the charge of sodium ion.
where,
q = charge of sodium ion
n = number of sodium ion = 
e = charge on electron = 
Now put all the given values in the above formula, we get:
Now we have to calculate the charge of chlorine ion.
where,
q' = charge of chlorine ion
n = number of chlorine ion = 
e = charge on electron =
Now put all the given values in the above formula, we get:
Now we have to calculate the current passing between the electrodes.
Thus, the current passing between the electrodes is,
The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is <span>Group 17, Period 2.</span>
Answer:
pV= nRT
Explanation:
(p1 × V1)/ T1/ (p2 × V2)/ T2
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute:
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025= 0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
= 0.0075 * 63.546 =0.477 g
