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Schach [20]
3 years ago
14

Ten runners join a race. In how many possible ways can they be arranged as first, second, and third placer? Pls answer

Mathematics
2 answers:
dybincka [34]3 years ago
7 0
Ans: 720

<span>This is equal to the number of different arrangements of three persons from a group of 10 persons </span>

Required number of ways = 10P3 = 720

OR can be solved in this way
select 3 runners (10C3 ways)
These 3 runners can be arranged in 3! ways
<span>Total = 10C3×3! = 720 .hope i was able to help :)</span>
Daniel [21]3 years ago
5 0
Ans: 720

<span>This is equal to the number of different arrangements of three persons from a group of 10 persons </span>

Required number of ways = 10P3 = 720

OR can be solved in this way
select 3 runners (10C3 ways)
These 3 runners can be arranged in 3! ways
<span>Total = 10C3×3! = 720

</span>
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For this case we have that by definition, a function is of the form:

y = f (x)

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3 years ago
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nirvana33 [79]
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