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vodomira [7]
3 years ago
12

Which trinomial is the product of the expression below?

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
Hope this helps you.

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A company uses paper cups shaped like cones for its water cooler. Each cup has a height of 12 cm, and the base has a radius of 5
Alex

Answer:

16.65 cups

Step-by-step explanation:

Step one:

height =12 cm, and

the base has a radius =5.5 cm

Volume of the cup = πr^2h

substitute we have

volume= 3.142*5.5^2*12

volume= 3.142*30.25*12

volume=1140.546cm^3

Step two:

volume of cooler=  18,997 cm^3

hence the number of cups to fill it is

=18,997/1140.546

=16.65 cups

4 0
3 years ago
The angles in a triangle are in the ratio 1 : 2 : 3.
vekshin1

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Keisha, Scott, and Ryan have a total of $101 in their wallets. Keisha has $6 more than Scott. Ryan has 3 times what Scott has. H
Yuri [45]

Answer:

Keisha =$25

Scott =$19

Ryan = $57

Step-by-step explanation:

Let the amount each have be represented by A, B and C

Keisha = A

Scott = B

Ryan = C

Keisha , Scott and Ryan have a total of $101.

That’s

A + B + C = $101

Keisha has $6 more than Scott

A = 6 + B

Ryan has 3 times Scott

C = 3B

Substitute 6+B for A and 3B for C in the first equation.

That’s

A + B + C = 101

6 + B + B + 3B = 101

6 + 5B = 101

Subtract 6 from both sides

6 - 6 + 5B = 101 - 6

5B = 95

Divide both sides by 5

B = 95/5

B = 19

Scott has $19

Recall Keisha has $6 more than Scott B.

That’s A = 6 + B

A = $6 + $19

A = $25

Keisha has $25

Also, Ryan C has 3 times what Scott B has .

That’s

C = 3 x B

C = 3 x 19

C = $57

Therefore, Keisha has $25, Scott has $19 and Ryan has $57

3 0
3 years ago
Lilly is placing an order for r bags of rice for her sushi restaurant. The market charges $15.70 per bag of rice. Which equation
Ipatiy [6.2K]
T = 15.70r
time cost (t) = the price of the bag of rice • the number of bags of rice
7 0
3 years ago
Which expression is equivalent to log Subscript w Baseline StartFraction (x squared minus 6) Superscript 4 Baseline Over RootInd
zysi [14]

Option b: 4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8}) is the correct answer.

Explanation:

The expression is \log _{w}\left(\frac{\left(x^{2}-6\right)^{4}}{\sqrt[3]{x^{2}+8}}\right)

Applying log rule, \log _{c}\left(\frac{a}{b}\right)=\log _{c}(a)-\log _{c}(b), we get,

\log _{w}\left(\left(x^{2}-6\right)^{4}\right)-\log _{w}(\sqrt[3]{x^{2}+8})

Again applying the log rule, \log _{a}\left(x^{b}\right)=b\cdot\log _{a}(x), we get,

4 \log _{w}\left(x^{2}-6\right)-\log _{w}(\sqrt[3]{x^{2}+8})

The cube root can be written as,

4 \log _{w}\left(x^{2}-6\right)-\log _{w}({x^{2}+8})^{\frac{1}{3} }

Applying the log rule, \log _{a}\left(x^{b}\right)=b\cdot\log _{a}(x), we have,

4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8})

Thus, the expression which is equivalent to \log _{w}\left(\frac{\left(x^{2}-6\right)^{4}}{\sqrt[3]{x^{2}+8}}\right) is 4 \log _{w}\left(x^{2}-6\right)-\frac{1}{3} \log _{w}({x^{2}+8})

Hence, Option b is the correct answer.

3 0
4 years ago
Read 2 more answers
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