The horizontal value at which the highest point of a variable's normal curve occurs is also the ____ of the variable.

1 answer:

4 0

The answer to the question mentioned above is "the mean" such as the whole sentence will become "The horizontal value at which the highest point of a variable's normal curve is also the MEAN of the variable". This is the answer.

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valentinak56 [21]

Question:

The angle $\theta_1$ is located in Quadrant III, and $sin(\theta_1) = - \sqrt{\frac{3}{2}}$ .

What is the value of $cos(\theta_1)$ ?

Express your answer exactly. $cos(\theta1) =$ ________

Answer:

$cos(\theta_1) = - \frac{1}{2}$

Step-by-step explanation:

Given:

$sin(\theta_1) = - \sqrt{\frac{3}{2}}$

Since the angle $\theta_1$ is located in Quadrant III, we have:

$sin(\theta_1) = sin(\pi + \frac{\pi}{3})$

$\theta_1 = \pi + \frac{\pi}{3}$

$\theta_1 = \frac{4 \pi}{3}$

Thus, $cos(\theta_1)$ =

$cos(\theta_1) = cos(\pi + \frac{\pi}{3})$

$cos(\theta_1) = -cos(\frac{\pi}{3})$

$cos(\theta_1) = - \frac{1}{2}$

3 0

4 years ago

How long is a rectangular field with a width of 3/5 mile and an area of 21/50 square mile?

Elan Coil [88]

$w=\frac{3}{5}mi\\\\l=?\\\\A_{\fbox{ }}=w\times l;\ A_{\fbox{ }}=\frac{21}{50}mi^2\\\\\frac{3}{5}l=\frac{21}{50}\ \ \ \ \ |multiply\ both\ sides\ by\ \frac{5}{3}\\\\l=\frac{21}{50}\times\frac{5}{3}\\\\l=\frac{7}{10}\\\\Answer:\boxed{\frac{7}{10}mi=0.7mi}$