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emmainna [20.7K]
3 years ago
5

What is the answer to 5x + 2 = 3x

Mathematics
2 answers:
Anna [14]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

5x+2=3x

2=-2x

x=-1

3241004551 [841]3 years ago
4 0

Answer:

  • x = -1

Explanation:

5x + 2 = 3x

5x - 3x = -2

2x = -2

x = \dfrac{-2}{2}

x = -1

Hope this helps! ☺

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tiny-mole [99]

Step-by-step explanation:

I would help i really would but I need more info discussing the topic im sorry but I can't answer it

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3 years ago
Find the value of the line integral. F · dr C (Hint: If F is conservative, the integration may be easier on an alternative path.
Harman [31]

Answer: a) Fdr = 0 b) Fdr = 0

Step-by-step explanation:

According to the integral Fdr

a) If r=t²i + t²j

If the field F(x, y, z) = y sin(z)i + x sin(z)j + xy cos(x)k

Integral Fdr = y sin(z)i + x sin(z)j + xy cos(x)k d(t²i + t²j)

Multiplying component wise.

Fdr = y sin(z)i(dt²i) + x sin(z)j(dt²j) + xy cos(x)k d(0k)

Remember that dot product of different components gives 'zero' i.e i.j = 0 etc.

Fdr = ysin(z)dt² + xsin(z)dt² + 0...(1)

Generally for 2dimensional object r=xi+yj

Comparing this to r = t²i+t²j

x=t² and y = t² z = 0...(2)

Substituting 2 into 1

Fdr = t²sin0dt² + t²sin0dt²

Integrating resulting Fdr with respect to t² within the limit 0 ≤ t ≤ 2, we have

Fdr = 0

b) since there is no z-component in the second part as well, integral of Fdr within the limit 0 ≤ t ≤ 1 will also be 0.

3 0
3 years ago
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 13.1 years; the standard devia
Ilia_Sergeevich [38]

Answer:

<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>

<em>The  Estimate  probability between 16.1 and 17.6 years = 2.14 years</em>

<em>Step-by-step explanation:</em>

<u><em>Step(i)</em></u>:-

Given the average of Population 13.1 years

The standard deviation of the Population = 1.5 years

<em>Let 'x' be the random variable in Normal distribution</em>

<em>Given x = 16.1</em>

         Z _{1} = \frac{x- mean}{S.D}

            =\frac{16.1-13.1}{1.5}

           = 2

       <em> Z₁ = 2</em>

<u><em>Step(ii):</em></u><em>-</em>

<em>Given x = 17.6</em>

      Z_{2}  = \frac{17.6- 13.1}{1.5}

<em>      Z ₂= 3</em>

<em> Z₁ = 2 and </em> <em>    Z ₂= 3 are both positive</em>

<em>The Estimate probability between 16.1 and 17.6 years</em>

<em>P( 16.1<x<17.6) = P( 2 < Z < 3)</em>

<em>                       </em> = A(3) - A(2)

                      =  0.49865 - 0.4772 (from normal table)

                     = 0.0214

<em>The probability between 16.1 and 17.6 years = 0.0214 years </em>

<em>                                                                        =  0.0214 ×100 </em>

<em>                                                                       = 2.14 years</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The  Estimate  probability between 16.1 and 17.6 years = 2.14 years</em>

                                                                                           

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