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AleksAgata [21]
3 years ago
10

Evaluate. −7×(−6)×5= -7×(-6)×5= ______

Mathematics
1 answer:
Lunna [17]3 years ago
7 0

Answer:

210

Step-by-step explanation:

double negatives = positive

-7 * -6 * 5 = 7 * 6 * 5 = 42* 5 = 210

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Find the equation of the line passing through (3,4), (-1,-2).
Kryger [21]

Answer:

(y-(-2))/(x-(-1)= (-2-4)/(-1-3)

(y+2)/(x+1)= (-6)/(-4)

(y+2)/(x+1)= (3/2)

Cross multiplying

2y+4= 3x+3

3x-2y-1=0

7 0
3 years ago
Write a expression to show 5 less than the sum of y and g
ddd [48]
Idk if this is correct but y+g>5 or 5<y+g
8 0
3 years ago
NO ONE EVER ANSWERS MY QUESTIONS I NEED HELP PLEASE!!! 2 problems Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM. a
almond37 [142]

To solve this problem we will use sinus theorem.

It's general form is

a/sinα = b/sinβ = c/sinγ  

In this case it reads ML/sin∡K = KL/sin∡M = KM/sin∡L  =>

ML/sin∡K = KL/sin∡M  =>  12/sin60° = KL/sin45° => 12/(√3/2) = KL/(√2/2) =>

2*12/√3 = 2*KL/√2 => We will divide whole equation with number 2 and get

12/√3=KL/√2 => KL*√3=12√2 => KL=(12√2)/√3

When we rationalize denominator we get  KL=4√6≈ 4*2.45= 9.8

Considering that we know two angles we will calculate the third

∡K+∡M+∡L=180° => 60°+45°+∡L=180° => ∡L= 180-105=75°

Reason- The theorem of the sum of the inner angles of the triangle

ML/sin∡K=KM/sin∡L => 12/sin60°=KM/sin75°

We will calculate  sin75° = sin (30+45)= sin30 *cos45+cos30*sin45 =>

sin75°= 1/2 * √2/2 = √3/2 * √2/2= √2/4 *(√3+1)≈(1.41/4)*(1.73+1)=0.96

12/(√3/2)=KM/0.96 => 12*2/√3=KM/0.96 => 13.87=KM/0.96 =>

KM=13.87*0.96= 13.31

Perimeter of ΔKLM => P=KL+ML+KM= 12+9.8+13.31= 35.11

In the same way you can calculate perimeter of ΔMNO.

Good luck!!!


4 0
3 years ago
In a chess match, a win counts as 1 point, a draw counts as 0.5 point, and a loss counts as 0 points. After 21 games between the
Natalija [7]

Answer:

14.5

Step-by-step explanation:


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