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gulaghasi [49]
3 years ago
13

HURRRYYYY PLZZ!!

Computers and Technology
2 answers:
vivado [14]3 years ago
6 0

Answer: A. How much is this vehicle's resale value?

AysviL [449]3 years ago
3 0
Answer : D is this vehicle currently in shape to safely get me to where I need to be
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You can use a server-side script as a ____ to access data from another domain.
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Nutka1998 [239]

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6 0
3 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn:
Rus_ich [418]
<h2><u>Answer</u>:</h2>

public class ArrayMethodDemo {

   public static void main (String args[]) {

       int[] numbers = {12, 15, 34, 67, 4, 9, 10, 7};

       int limit = 12;

       display(numbers);

       displayReverse(numbers);

       displaySum(numbers);

       displayLessThan(numbers, limit);

       displayHigherThanAverage(numbers);

   }

   

   public static void display(int[] numbers) {

       

       //Message to be displayed before printing out the numbers

      System.out.print("Numbers in the array: ");

       

       //loop through the numbers in the array and print each number

       for(int x: numbers){

           System.out.print(x + " ");

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displayReverse(int[] numbers) {

       

       //Message to be displayed before printing out the reverse of the array

       System.out.print("Reverse of the array numbers: ");

       

       

       //loop through the array starting from the last index

       for(int i = numbers.length - 1; i > 0; i--){

           System.out.print(numbers[i] + " ");

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displaySum(int[] numbers) {

       

       //initialize the sum variable

       int sum = 0;

       

       //loop through the array and add each element to sum

       for(int i = 0; i < numbers.length; i++){

           sum += numbers[i];

       }

       

       //print out the sum

      System.out.println("Sum: "  + sum);

       

   }

   

   public static void displayLessThan(int[] numbers, int limit) {

       

       //Text to be displayed before printing values less than the limit

       System.out.print("Values less than limit (" + limit + "): ");  

       //loop through the array and print numbers lower than the specified limit

       for(int i = 0; i < numbers.length; i++){

           if(numbers[i] < limit){

               System.out.print(numbers[i] + " ");

           }

       }

       

       //print a new line

       System.out.println();

   }

   

   public static void displayHigherThanAverage(int[] numbers) {

       //initialize the average variable

       double average = 0.0;

       

       //initialize the sum variable

       int sum = 0;

       

       

       //loop through the array and add each element to sum

      for(int i = 0; i < numbers.length; i++){

           sum += numbers[i];

       }

       

       //calculate the average

      average = sum / numbers.length;

       

       //Message to be displayed before printing the values higher than the average

       System.out.print("Values higher than average (" + average + "): ");

       

       

       //loop through the array and print numbers higher than the calculated average

      for(int i = 0; i < numbers.length; i++){

           if(numbers[i] > average){

               System.out.print(numbers[i] + " ");

           }

       }

       

       //print a new line

       System.out.println();

   }

   

}

<h2><u>Sample Output:</u></h2>

Numbers in the array: 12 15 34 67 4 9 10 7  

Reverse of the array numbers: 7 10 9 4 67 34 15  

Sum: 158

Values less than limit (12): 4 9 10 7  

Values higher than average(19.0):34 67

<h2>Explanation:</h2>

The code above contains comments explaining important parts of the code. Kindly go through the comments. A sample output, arising from running the application, has also been added to ace understandability.

6 0
3 years ago
The equation x + y2-4x+2y=b describes a circle.
liberstina [14]

Answer:

-1

Explanation:

The given equation can be written as

-3x +y^2 +2y +1=b+1

-3x +(y+1)^2=b+1

(-3x-b)+ (y+1)^2=1

This is to be compared with (x-a)^2 + (y-b)^2=c^2

where (a,b) is the center, and c is the radius of the circle.

Thus, we get y=-1, and this is our answer.

6 0
4 years ago
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