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Goshia [24]
3 years ago
9

Please help!! ill give a brainliest!!

Mathematics
1 answer:
marin [14]3 years ago
6 0

Answer:

<u>y - 2= -5(x + 3)</u>... (the red one) is the correct answer!!!

HOPE THIS HELPED!!!

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What is one half ( 1/2 ) squared?
lorasvet [3.4K]

Answer:

(\frac{1}{2} )^{2} =\frac{1^2}{2^2} = \frac{1} {4}}

When squaring a fraction, square both numerator AND denominator

7 0
3 years ago
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PLZZZZ HELPPPPPP THIS IS TIMEDDDD!!!! *look at picture*
Kazeer [188]

Answer:

Height of the building = 50.8 ft

Step-by-step explanation:

A person and a building are casting the shadows at the same time of the day.

Triangles formed by the person and his shadow and the building and its shadow will be similar.

Therefore, corresponding sides of the similar triangles will be proportional.

\frac{x}{28}=\frac{5.8}{3.2}

x = \frac{5.8\times 28}{3.2}

x = 50.75

x ≈ 50.8 ft

5 0
3 years ago
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Please answer quickly<br><br><br><br><br> 40 points
Elis [28]

Answer:

2/5 hour is closest to 0 1/2 hours, 5/8 hour is closest to 1/2 hour. Therefore, the best estimate for the total time Maria spent with her sister is close to 1 hour

Step-by-step explanation:

We can represent the time Maria spends playing the game as 0.4, since 2/5 as a fraction is 0.4. This is closer to 1/2, which is 0.5 then it is to 0, because 4 is closer to 5 then 0. Then, we can represent the time Maria reads the book as 0.625, which is closer to 1/2 then it is to 1. Now we can add the estimated times. 1/2+1/2=1 hour

8 0
2 years ago
If h(x) is the inverse of f(x), what is the value of h(f(x))?
Mekhanik [1.2K]
Hello,

f(x) has as inverse f^(-1)(x)
and (fof^(-1))(x)=(f^(-1)of)(x)= x (the neutral function)
so h(f(x))=x

8 0
3 years ago
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If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
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