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MakcuM [25]
3 years ago
7

Factor

"TexFormula1" title=" \frac{18 x^{-2}y ^{2} }{2 x^{2} y} " alt=" \frac{18 x^{-2}y ^{2} }{2 x^{2} y} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
GuDViN [60]3 years ago
6 0
When you write terms in denominator on numerator, sign of indices changes.
\frac{18x^{-2}y^{2}}{2x^{2} y} =  \frac{(18x^{-2}y^{2})*(x^{-2}y^{-1})}{2} 
 = 9(x^{-4} y^{1})
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3 years ago
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stiks02 [169]

The value of scale k is 3

Step-by-step explanation:

In order to find the scale , we can either divide the coordinates of H' by the original point or compare both the points to find the original ordered pair.

Given

H(3,4)

H'(9,12)

The coordinates of H are multiplied with some integer k to form H'

So,

<u>For x-coordinate:</u>

3k = 9

k = 9/3 = 3

<u>For y-coordinate:</u>

4k = 12

k = 12/4 = 3

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The value of scale k is 3

Keywords: Coordinate geometry, scaling

Learn more about scaling at:

  • brainly.com/question/4771355
  • brainly.com/question/4786449

#LearnwithBrainly

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goblinko [34]

Answer:

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168....<em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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