Ask question

Ask question

All categories

3 years ago

7

Factor

"TexFormula1" title=" \frac{18 x^{-2}y ^{2} }{2 x^{2} y} " alt=" \frac{18 x^{-2}y ^{2} }{2 x^{2} y} " align="absmiddle" class="latex-formula">

1 answer:

GuDViN [60]3 years ago

6 0

When you write terms in denominator on numerator, sign of indices changes.
$\frac{18x^{-2}y^{2}}{2x^{2} y} = \frac{(18x^{-2}y^{2})*(x^{-2}y^{-1})}{2} 
 = 9(x^{-4} y^{1})$

You might be interested in

Can someone tell me the answers

LiRa [457]

Question 4- is 32.25
question 5- is 12.4
question 6 -is 14/17
question 7 - is 10.7

4 0

3 years ago

Line $\ell_1$ is horizontal and passes through $(1,1)$. Line $\ell_2$ is vertical and passes through $(2,2)$. Find the point of

borishaifa [10]

Answer:

(2,1)

Step by step explanation:

Please find the attachment.

We have been given that line $l_1$ is horizontal and passes through point (1,1). Line $l_2$ is vertical and passes through point (2,2). We are asked to find point of intersection of line $l_1$ and line $l_2$ .

Line $l_1$ is a horizontal line so y-coordinate will be 1 for any value of x. Line $l_2$ is a vertical line, so x-coordinate will be 2 for any value of y.

Therefore, intersection point of both lines will include x-coordinate of line $l_2$ and y-coordinate of line $l_1$ that is (2,1).

5 0

3 years ago

7(5-4x) in distributive property

kati45 [8]

Answer:

Distributive Property : <em><u>a(b+c)= ab+ac</u></em>

7(5-4x) = (35-28x) ★

<h3><u>(35-28x)</u> is the right answer.</h3>

3 0

3 years ago

For the following figure what’s the value of x?

Leto [7]

Answer:

x = 8 in

y = 8sqrt(2) in

Step-by-step explanation:

x = 8

AC = BC

Because opposite angles are equal.

8² + 8² = hyp²

hyp² = 64 + 64 = 128

hyp = sqrt(128)

hyp = 8sqrt(2)

Where sqrt is the square root

8 0

3 years ago

Solve x2 – 7x = –13.

aleksklad [387]

we have

$x^{2} -7x=-13$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} -7x+3.5^{2}=-13+3.5^{2}$

$x^{2} -7x+12.25=-13+12.25$

$x^{2} -7x+12.25=-0.75$

Rewrite as perfect squares

$(x-3.5)^{2}=-0.75$

remember that

$i=\sqrt{-1}$

Square root both sides

$(x-3.5)=(+/-)\sqrt{-0.75}$

$(x-3.5)=(+/-)\sqrt{-1*0.75}$

$(x-3.5)=(+/-)\sqrt{0.75}i$

$x1=3.5+\sqrt{0.75}i$

$x2=3.5-\sqrt{0.75}i$

Simplify

$\sqrt{0.75}=\frac{\sqrt{3}}{2}$

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

therefore

<u>the answer is</u>

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

6 0

3 years ago

Read 2 more answers