A=x(1+r/n)^nt
21150=x(1+0.032/12)^84
21150=x(1+0.0026666)^84
21150=x(1.002666666)^84
21150=x(1.25069809)
21150/1.25069809=x
16910.56=x
Hope this helps!
Answer:
c = 9
Step-by-step explanation:
9c - 10 = 2c + 53
9c =2c + 63
7c = 63
c = 9
The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.<span>
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5000(1+.07)^2
5000(1.07)^2
5000(1.14)
5,700
Your final answer should be 5,700$. If you wanna double check you would use the equation fv=bv(1+r/m)^mt
