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3 years ago

The greater the value of m (slope), the ______ the line!

Mathematics

1 answer:

Law Incorporation [45]3 years ago

8 0

Answer:

the Steeper the line.

Step-by-step explanation:

A slope of 1 is steeper than a slope of 1/2.

A slope of 2 is steeper than 1, and a slope of 3 is steeper. The number sells how many units up or down the graphed line rises for each unit of run from left to right.

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Which system of linear equations appears to have a solution of (–1, 4)? On a coordinate plane, 2 lines intersect at (1, negative

madam [21]

Answer:

On coordinate plane, 2 lines intersect at (negative 1, 4)

Step-by-step explanation:

negative 1 = -1, 4 = 4

therefore this means that this coordinate is also (-1, 4)

6 0

3 years ago

Read 2 more answers

An angle measures 120°less than the measure if its supplementary angle. What is the measure of each angle

marissa [1.9K]

Answer: 60°

Step-by-step explanation: 180 - 120 = 60.

7 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Which is true regarding the graphed function f(x)

KiRa [710]

Answer:

Step-by-step explanation:

f(0) = 3

of(5) = -1

f(3) = 2

-3 -2 -14

f(2)= -2

5 0

2 years ago

The prime factorization of 396 is _____ .

Elena L [17]

Answer:

396 : 2 * 2 * 3 * 3 * 11

Step-by-step explanation:

using long division of prime factors, you will end up with the following:

396 : 2 * 2 * 3 * 3 * 11

4 0

3 years ago