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4 years ago

13

2/5 + (5^2-10) / 5^2

1 answer:

Vadim26 [7]4 years ago

4 0

$\bf \cfrac{2}{5}+\cfrac{5^2-10}{5^2}\implies \cfrac{2}{5}+\cfrac{~~\begin{matrix} 5^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 5^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}-\cfrac{10}{5^2}\implies \cfrac{2}{5}+1-\cfrac{10}{25}\implies \cfrac{2}{5}+1-\cfrac{2}{5}\implies 1$

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Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet:

Phoenix [80]

6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

<u>Step-by-step explanation:</u>

We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:

Trenton's pet: 4/5 cup of dry food•

With 4/5 per day , for 14 days :

⇒ $14(\frac{4}{5} )$

⇒ $14(0.8 )$

⇒ $11.2$

Maria's pet: 1.25 cups of dry food.

With 1.25 per day , for 14 days :

⇒ $14(1.25 )$

⇒ $17.5$

Subtracting Maria's - Trenton's :

⇒ $17.5-11.2=6.3$

That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks

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4 years ago

Using exact values (e.g. 10+4π), find the area of the following composite shape:

Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

Rectangle + circle - semicircle

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Answer:

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3 years ago

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Mariulka [41]

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Rzqust [24]

Answer:

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3 years ago

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