Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
Answer:
It will take the car 13.5 minutes to travel 3.5 miles.
For the compound B the following statement is correct-
B. It is an ether because it is unable to form a hydrogen bond, so it is less soluble in water.
The solubility of alcohol in water depends upon the capability of formation of hydrogen bond in the solute. Now in alcohol the -OH group is polar in nature which enhance the possibility of hydrogen bond formation and it is more soluble in water.
On the other hand although there presence a -O- functional group in ether. It is less soluble in water due to non polarity of the functional group.
From the given data it is seen that compound A is more soluble in water than compound B. Thus it may be predicted that compound A is alcohol and B is ether.
Henceforth, for the compound B the following statement is correct-
B. It is an ether because it is unable to form a hydrogen bond, so it is less soluble in water.
The reason of incorrect options:
A. compound B cannot be an alcohol as it is less soluble in water.
C. In ether the functional group is -O-, thus electronegative atom (O) is present.
D. As both the compound (alcohol and ether) has equal molecular mass thus the organic chain will be same in alcohol and the hydrogen bond interaction will be more prominent than the dispersion force between the -OH group.
Answer:
8 moles of C
Explanation:
From the question given above, the following equation was obtained:
3A + 2B —> 6C
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C
Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B
