How many grams in 2.5 mol of NaCi
1 answer:
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Answer:
- <em>0.138 kcal</em>
Explanation:
The answer choices are:
- a) 5.78 × 10⁵ kJ
- b) 138 kcal
- c)0.138 kcal
- d)1.38 × 10⁵ kcal
You must use the conversion factors to convert J to kcal.
- 1cal = 4.184J
Dividing both sides by 4.184J:
⇒ 1 = 1cal/4.184J
- 1kcal = 1,000cal
Dividing both sides by 1,000 cal
⇒ 1 = 1kcal / 1,000 cal
Mutiply<em> 578J</em> by the conversion factors to find <em>kcal</em>:
Notice how the units J and cal cancel to yield kcal at the end.
Hello!
The ball took up 2,9L
To solve this problem, we should apply the ideal gas law and clear for n (the number of moles), as this value doesn't change when Devin takes the ball to the garage:
Now, we should clear this equation to find V2, as this is the value we are looking for:
≈2,9L
Have a nice day!
The ball took up 2,9L
To solve this problem, we should apply the ideal gas law and clear for n (the number of moles), as this value doesn't change when Devin takes the ball to the garage:
Now, we should clear this equation to find V2, as this is the value we are looking for:
Have a nice day!