All categories

3 years ago

Which salt is not derived from a strong acid and a strong soluble base? 1. liclo4 2. csbr2 3. mgcl2 4. ba(no3)2 5. nai?

2 answers:

7 0

3. MgCl2 For each salt, determine what acid and base were used to create it by separating the salt into it's cation and anion. From there, determine the acid and base used to create the salt by adding the appropriate number of hydroxyl group(s) to the cation and hydrogen to the anion. So: LiClO4 -> Li, ClO4 -> LiOH + HClO4. LiOH is a strong base, and HClO4 is a strong acid. CsBr2 -> Cs, Br2 -> CsOH + HBr2 CsOH is a strong base, and HBr2 is a strong acid. MgCl2 -> Mg, Cl2 -> Mg(OH)2 + HCl Mg(OH)2 is not a strong soluble base HCl is a strong acid. Therefore MgCl2 is the correct salt. Ba(NO3)2 -> Ba, NO3 -> Ba(OH)2 + HNO3 Ba(OH)2 is a strong base, and HNO3 is a strong acid. NaI -> Na, I -> NaOH + HI NaOH is a strong base, and HI is a strong acid.

lianna [129]3 years ago

4 0

I believe the answer is MgCl, this is because the bases of group one elements (alkali metals) such as sodium, lithium , and cesium, are all strong bases unlike those of group 2 and group 3. The bases of group one elements ( NaOH, LiOH, CsOH) all readily dissolve in water forming strong soluble base. Then between a base of Ba (Ba(OH)2)and that of Mg, (Mg(OH)2), the one for Ba is more stronger because Ba is more reactive than that of Mg because it is not readily dissolve in water ( less soluble in water to give OH- ions)

You might be interested in

Assign an oxidation number to each element in the following species. H2O

VikaD [51]

Answer:

the oxidation number of hydrogen is +2, while oxygen is -2

5 0

4 years ago

Determine the molecular and empirical formulas for the substance shown in the ball-and-stick model below.

notka56 [123]

Molecular formula: C8H6N2

Empirical formula: C4H3N

8 0

3 years ago

QUESTION 3 Consider a solution containing 0.80 M NaF and 0.80 M HF. Calculate the moles of HF and the concentration of HF after

Lisa [10]

Answer:

0.056moles HF and 0.70M

Explanation:

When a strong acid is added to a buffer, the acid reacts with the conjugate base.

In the system, NaF and HF, weak acid is HF and conjugate base is NaF. The reaction of NaF with HCl (Strong acid) is:

NaF + HCl → HF + NaCl

Initial moles of NaF and HF in 60.0mL of solution are:

NaF:

0.0600L × (0.80mol / L)= 0.048 moles NaF

HF:

0.0600L × (0.80mol / L)= 0.048 moles HF

Then, the added moles of HCl are:

0.0200L × (0.40mol / L) = 0.008 moles HCl.

Thus, after the reaction, moles of HF produced are 0.008 moles + the initial 0.048moles of HF, moles of HF are:

0.056moles HF

In 20.0mL + 60.0mL = 80.0mL = 0.0800L, molarity of HF is:

0.056mol HF / 0.0800L = 0.70M

6 0

3 years ago

After pyruvate oxidation, the chemical energy of how many carbons of the original glucose molecule is converted to chemical ener

Mars2501 [29]

I believe the answer is 4 carbons. Glycolysis involves break down of glucose to two molecules of pyruvic acid (3 carbons) under aerobic conditions. At the end of glycolysis the two pyruvate molecules undergoes pyruvate oxidation to capture the remaining energy in the form of ATP. A carboxyl group is removed from pyruvate and released in the form carbon dioxide, leaving a two carbon molecule which forms Acetyl-CoA (2 molecules). Acetyl-CoA then serves as a fuel for the citric acid cycle in the next stage of cellular respiration.

4 0

3 years ago

In the Cannizzaro reaction of benzaldehyde ( aka solventless disproportionation of benzaldehyde in the presences of a strong bas

choli [55]

Answer:

Reaction products are shown below

Explanation:

In cannizaro reaction, benzaldehyde produces benzoic acid and benzyl alcohol through disproportion.
Here, a hydroxyl group first gives a nucleophilc addition at carbonyl center of benzaldehyde.
Then a hydride transfer takes place to another molecule of benzaldehyde
Thus, benzoic acid and benzyl alcohol are produced.
Full reaction mechanism has been shown below

8 0

4 years ago