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3 years ago

5

The high temperature one day was 30 Fahrenheit. Then the temperature dropped 23 degrees during the night. Does the expression 30

+ (-23) represent the temperature at night? Explain.

1 answer:

erastovalidia [21]3 years ago

5 0

Answer:

This is a single a step problem. When you subtract a positive you can flip the signs.

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Write an exponential function in the form y=ab^x that goes through points (0,14) and (3,3024).

Dmitrij [34]

Answer:

y = 14 $(6)^{x}$

Step-by-step explanation:

For an exponential function of the form y = a $b^{x}$

Use the given points to find a and b

Using (0, 14 ), then

14 = a $b^{0}$ ( $b^{0}$ = 1 ) , thus

a = 14

y = 14 $b^{x}$

Using (3, 3024 ) , then

3024 = 14 b³ ( divide both sides by 14 )

216 = b³ ( take the cube root of both sides )

b = $\sqrt[3]{216}$ = 6 , thus

y = 14 × $6^{x}$ ← exponential function

5 0

3 years ago

An engineer is designing a storage compartment in a spacecraft .The compartment must be 2 meters longer than it is wide, and its

serg [7]

Answer:

Let x be the width of the compartment,

Then according to the question,

The length of the compartment = x + 2

And the depth of the compartment = x -1

Thus, the volume of the compartment, $V = (x+2)x(x-1) = x^3 + x^2 - 2x$

But, the volume of the compartment must be 8 cubic meters.

⇒ $x^3 + x^2 - 2x = 8$

⇒ $x^3 + x^2 - 2x - 8=0$

⇒ $(x-2)(x^2+3x+4)=0$

If $x-2=0\implies x = 2$ and if $x^2+3x+4=0\implies x = \text{complex number}$

But, width can not be the complex number.

Therefore, width of the compartment = 2 meter.

Length of the compartment = 2 + 2 = 4 meter.

And, Depth of the compartment = 2 - 1 = 1 meter.

Since, the function that shows the volume of the compartment is,

$V(x) = x^3 + x^2 - 2x$

When we lot the graph of that function we found,

V(x) is maximum for infinite.

But width can not infinite,

Therefore, the maximum value of V(x) will be 8.

8 0

3 years ago

Read 2 more answers

What eigen value for this matix <br> (1 -2)<br> (-2 0)

natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

Compute the matrix $A' = A-\lambda I$ , where I is the identity matrix (1s on the diagonal, 0s elsewhere)
Compute the determinant of A'
Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

$A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]$

The determinant of this matrix is

$\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4$

Finally, we have

$\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}$

So, the two eigenvalues are

$\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}$

5 0

2 years ago

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Los nutriólogos recomiendan que una persona debe tomar en promedio 2.5 litros de agua en un día, para que esté bien hidratada. ¿

Goshia [24]

the question in English

Nutritionists recommend that a person should drink an average of 2.5 liters of water in a day, to be well hydrated. How many liters of water should a person drink in a month to comply with a good hydration (Consider a month equal to 30 days) Formulate an algebraic expression to determine the total liters of water that a person should drink a given number of days.

Let

x-------> the number of days

y------> the total liters of water

we know that

$y=2.5x$ ------> algebraic expression to determine the total liters of water that a person should drink a given number of days

For x=30 days (1 month)

substitute in the formula

$y=2.5*30=75\ liters$

therefore

<u>the answer is</u>

$75\ liters$

7 0

3 years ago

Please hurry!!!

OlgaM077 [116]

The answer would be x=6

3 0

3 years ago

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