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3 years ago

How do you round a decimal to the nearest degree?

Mathematics

1 answer:

sineoko [7]3 years ago

7 0

By multiplying the round with the decimal number and you get the nearest degree

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Which expression is equivalent to 2x - 17?

liraira [26]

2x - 17?

= -17 +2x (using commutative property of addition, changing order and sum remains the same)

answer is A) -17 + 2x

8 0

3 years ago

Read 2 more answers

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers

PLEASE HELP IVE ASKED THIS QUESTION 3 TIMES PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!

worty [1.4K]

THEOREM:

h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.

ANSWER:

[3] By pythagorean theorem,

x² = 14² + 9²
x² = 196 + 81
x² = 277
x = √277
x = 16.64 rounded.

[4] By pythagorean theorem,

x² = 32² + 24²
x² = 1024 + 576
x² = 1600
x = √1600
x = 40.

[5] By pythagorean theorem,

(2x)² = 21² – 12.6²
4x² = 441 – 158.76
4x² = 284.24
x² = 284.24/4 = 70.56
x = √70.56
x = 8.4

[6] By tangent property,

7x – 29 = 2x + 16
7x – 2x = 16 + 29
5x = 45
x = 9.

So, WX = 7(9) – 29 = 63 – 29

WX = 34

4 0

3 years ago

A car's position is given by s(t) = {3 – 5t? + 7t hundreds of meters with t in minutes.

Nadya [2.5K]

Answer:

A) (1 s, 2.3 s)

B) (-4 m/s², 3.8 m/s²)

Step-by-step explanation:

The car's position which is the distance is given by the equation;

s(t) = t³ - 5t² + 7t

A) Velocity is the first derivative of the distance. Thus;

v(t) = ds/dt = 3t² - 10t + 7

At v = 0, we have;

3t² - 10t + 7 = 0

Using quadratic formula, we have;

t = 1 and t = 2.3

Thus, time at velocity of 0 is t = (1 s, 2.3 s)

B) acceleration is the derivative of the velocity. Thus;

a(t) = dV/dt = 6t - 10

At velocity of 0, we got t = 1 and t = 2.3

Thus;

a(1) = 6(1) - 10 = -4 m/s²

a(2.3) = 6(2.3) - 10 = 3.8 m/s

Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)

8 0

2 years ago

Cole rode his bike twice as far as Anita did today. Is this situation modeled by an expression or equation? How do you know?

Over [174]

Answer:

equation

Step-by-step explanation:

Let X is the distance that Anita rode

Let Y is the distance that Cole rode

Cole rode his bike twice as far as Anita, which mean:

Y = 2X

So this situation modeled by an equation

8 0

3 years ago