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sasho [114]
3 years ago
6

The price of an item has been reduced by $2.58.The original price was $17.84.What is the price now?

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

$15.26

Step-by-step explanation:

First, 17.84 - 2.58 = 15.26

Hope this helps!

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Alison’s age is 12 more than half of Sam’s age. Using S to represent Sam’s age, write an expression that represents Alison’s age
UNO [17]

Answer: the answer is C

Step-by-step explanation:

6 0
3 years ago
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Evaluate 5 - 44 * (-0.75) - 18 / 2/3 * 0.8 + (-4/5)
jenyasd209 [6]

Answer:

15.6

step by step explanation:

5-44• (-0.75) - 18 ÷ 2/3 • 0.8 + (-4/5)

= 5 + 33 - 27*0.8 - 0.8

= 5 + 33 -21.6 - 0.8

= 15.6.

8 0
3 years ago
9999999999999999999999999999999999999+888888888888888888888888888888888888
alexandr1967 [171]

Answer:

a lot

Step-by-step explanation:

3 0
3 years ago
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
3 years ago
↓↓ASAP PLAS HELP WILL GIVE BRAINLYEST WILL GIVE BRAINLYEST↓↓
Stels [109]

we know that

diameter of the base of a cylindrical can= 4 in----------> r=2 in

h=6.5 in

[surface area]=2*[pi*r²]+[2*pi*r*h]

then

[surface area]=2*[pi*2²]+[2*pi*2*6.5]=[ 25.13 ]+[ 81.68 ]=106.81 in²

the answer is 106.8 in²

3 0
3 years ago
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