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Kaylis [27]
3 years ago
7

Help? We learned this last year but I’m dumb soooooo yeee

Mathematics
2 answers:
eimsori [14]3 years ago
8 0

Answer:

x = 14

Step-by-step explanation:

When angles are complementary, it means that they add up to 90°.

This means that (4x)°+(2x+6)° = 90°, or (4x)+(2x+6) = 90  (Got rid of degree signs).

Now solve for x.

(4x)+(2x+6) = 90

simplify

4x+2x+6 = 90

-6 both sides

4x+2x = 84

simplify

6x = 84

÷6 both sides

x = 14

Komok [63]3 years ago
6 0

Answer:

14

Step-by-step explanation:

the sum of the terms in the angle is 6x+6. Since the angles ate complementary their sum is 90 so you set the aforementioned sum equal to 90. You then solve for x and get 14.

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Solve for x <br><br> Please show your work <br><br> Thank you
Licemer1 [7]
6-4=2
5-X=?
5-2=3
X=3
That is the answer, sorry if i didn't explain it well<span />
6 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
What is the degree of vertex A?
GREYUIT [131]

Answer:

  c.  6

Step-by-step explanation:

The degree of a vertex is the number of arc ends that intercept it. (The other end of the arc is irrelevant.)

Vertex A is connected to B (1), D (2), F (1), and itself (2). There are a total of 6 arc ends that meet vertex A. Its degree is 6.

7 0
3 years ago
If LN = 12x + 16, what is the length of Line segment L N in units?
elena55 [62]

Answer:

LN = 64 units

Step-by-step explanation:

Given M lies on LN, so LN = LM + MN --------------(1)

LN = 12x + 16

LM = 10x + 8

MN = 5x - 4

Substituting the values in equation 1, we get:

12x + 16 = (10x + 8) + (5x - 4)

12x + 16 = 15x + 4

15x - 12x = 16 -4

3x=12

Therefore x=4

LN= 12(4) + 16 = 64 units

3 0
2 years ago
Use 2 as a factor to write an expression that is equivalent to the ​expression 8x+6y . ​
posledela
2(4x + 3y). You just factor out the two
6 0
3 years ago
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