Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
When you calculate 2x-3=2x-5 it’s going to lead as -3=-5, therefore this statement is inaccurate and doesn’t have a value of x, it doesn’t even have a solution.
Answer:4^2≈50.26548
Step-by-step explanation:
πr2.
Where r is the radius and π≈3.14 , the ratio of a circle's circumference to its diameter.
Plugging in 4 from the radius, we get.
42π
⇒16π inches.
This is our exact answer. Alternatively, we can plug in 3.14 for π to get.
50.26 inches.
Right your ratio of

Simplify fraction to 3/4
Now set it up with c/100 to find the percent (c equaling the percentage of caremel brownies)
Cross multiplty:

Crossmultiply:
3c = 200
Divide (solve equation)
c = <span>
66.6666666667</span>
Answer:
The values of x which would give an area of 240m² would be:

Step-by-step explanation:
Given
The base of triangle b = 2x+1
The height of triangle h = 6x-3
The Area of the triangle A = 240 m²
The Area of the triangle has the formula
A = 1/2 × b × h
substituting b = 2x+1, h = 6x-3 and A = 240



Subtract 480 from both sides




Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)

solving


Divide both sides by 2


also solving


Divide both sides by 2


Therefore, the values of x which would give an area of 240m² would be:
