Question

Write the equation of a line that has a slope of 3 and goes through points (2,1)

Answer 1

Answer:

The equation of straight line is 3 x-y-5=0

Step-by-step explanation:

The equation of straight line having slope m = 3 and passing through the point (2,1) is

the standard form of straight line is $y-y_{1} = m (x-x_{1} )$

now substitute m = 3 and point (2,1) is

$y- 1 = 3(x-2)$

$y - 1 = 3 x - 6$

$3 x-y -6+1=0$

$3 x-y -5 =0$

The equation of straight line is 3 x-y-5=0