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2 years ago

Write the equation of a line that has a slope of 3 and goes through points (2,1)

Mathematics

1 answer:

Inga [223]2 years ago

3 0

Answer:

The equation of straight line is 3 x-y-5=0

Step-by-step explanation:

The equation of straight line having slope m = 3 and passing through the point (2,1) is

the standard form of straight line is $y-y_{1} = m (x-x_{1} )$

now substitute m = 3 and point (2,1) is

$y- 1 = 3(x-2)$

$y - 1 = 3 x - 6$

$3 x-y -6+1=0$

$3 x-y -5 =0$

The equation of straight line is 3 x-y-5=0

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A computer company has a special going in which all customers receive a free monitor and scanner with the purchase of a new comp

nataly862011 [7]

Answer:

C, $ 240,000.00

Step-by-step explanation:

Company cost: 393.29 + 151.44 + 46.39 = 591.12

Profit each computer: 1196.91 - 591.12 = 605.79

408 customers: 605.79 x 408 = 247162 ≈ 240000

4 0

2 years ago

Seth’s father is thinking of buying his son a six-month pass for $40. With the pass, matinees cost 1.00. If matinees are normall

mr Goodwill [35]

Answer:

The number of times Seth attend in order for the benefit his father to buy the pass is 2.8 times .

Step-by-step explanation:

Given as :

The price for six month pass = $ 40

The cost of matinees with the pass = $ 1.00

The cost of matinees without pass = $ 3.50

Now, According to question

If we take matinees per day for six months so, number of matinees = 6 × 30 = 180

So, The cost of matinees for six month with pass at the rate $ 1.00 each = 180 × $ 1 + $ 40

I.e The cost of matinees for six month with pass $ 220

Now, Again

The cost of matinees for six month without pass at the rate $ 3.50 each = 180 × $ 3.50

I.e The cost of matinees for six month without pass at the rate $ 3.50 each = $ 630

So, The number of times Seth attend in order for the benefit = $\frac{630}{220}$ = 2.8

Hence The number of times Seth attend in order for the benefit his father to buy the pass is 2.8 times . Answer

7 0

3 years ago

Can somebody plz help me with surveys in math?

Gre4nikov [31]

What are the surveys??

7 0

2 years ago

Add (1.3t3 + 0.4t2 – 24t) + (8 – 18t + 0.6t2) For each term in the second polynomial, enter the letter showing where that term s

nignag [31]

Answer:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

Step-by-step explanation:

Given

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Required

Solve

We have:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2)$

Collect like terms

$1.3t^3 + 0.6t^2 + 0.4t^2 - 24t- 18t + 8$

$1.3t^3 + t^2 -42t + 8$

So:

$(1.3t^3 + 0.4t^2 - 24t) + (8 - 18t + 0.6t^2) = 1.3t^3 + t^2 -42t + 8$

8 0

2 years ago

Solve 4X^2+7 = 8X +4 by using the quadratic formula

Sergio [31]

Answer:

(1.5,0)

(.5,0)

Step-by-step explanation:

Quadratic formula below

We first need to move everything to one side of the equation

4x²-8x+3=0

Then plug everything in

(8±√(-8²-4*4*3))/(2*4)

(8±√16)/8

To calculate the ± we need to do when where it's adding and then negative

we have

(8+4)/8=3/2

and hten

(8-4)/8=1/2

4 0

3 years ago