C)
Area of full triangle
1/2(8)(6)=24cm^2
Area of non shaded triangle
1/2(4)(3)=6cm^2
Area of full minus area of small triangle
24-6=18cm^2
D)
Area of Big rectangle
(4)(12)=48
Area of non shaded triangle
1/2(9)(4)=18
Area of Big rectangle minus non shaded triangle
48-18=30cm^2
Answer:
Step-by-step explanation:
It is given that AC:CM = 3:4.
Therefore, let AC = 3k and CM = 4k
It is given that Δ ACM is right angled.
Therefore,
AM = 5k
But, AM = MP + AP
Therefore, MP + AP = 5k --- (1)
It is given that MP - AP = 1 --- (2)
Multiply (1) and (2), we get.
(MP + AP)(MP - AP) = 5k × 1 = 5k
Add and subtract 
on the left side.
--- (3)
But, since CP ⊥ AM, Δ CMP and Δ CAP are right triangles. Therefore,
and
Now, (3) becomes,
7k = 5 or
AM = 5k
I think of these in terms of "short side", "long side" and "hypotenuse." The proportions will be true that equate the ratios of corresponding sides.
I is (long side of CDB)/(short side of CDB) = (long side of BDA)/(short side of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
II is (hypotenuse of CBA)/(long side of CBA) = (long side of CBA)/(hypotenuse of CBA)
This proportion equates a value to its inverse, so is <em>false</em> (since the triangle has non-zero area)
III is (long side of CBA)/(short side of CBA) = (hypotenuse of CBD)/(long side of CBD)
The sides involved here are not corresponding, so this is <em>false</em>.
IV is (long side of CDB)/(hypotenuse of CDB)/(long side of BDA)/(hypotenuse of BDA)
These are corresponding sides, so the proportion is <em>true</em>.
The appropriate choice is ...
... a. I and IV only
He spent $33 to fix the lawnmower
If you add up all the values you get $64 so he spent $33 because if you add 33 to 31(his week value) you get 64 l.
