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evablogger [386]
3 years ago
14

How many real and how many are imaginary Please Explain how to do it

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

There are no real solutions, and 2 imaginary solutions.

Step-by-step explanation:

There are no real solutions since the function never touches the x-axis and it does not have any roots. Imaginary solutions always come in pairs, and since the exponent degree of x is 2, there are 2 solutions to the problem. You can find the imaginary solutions by plugging the equation into the quadratic formula.

Doss [256]3 years ago
4 0

Answer:

no idea bud

Step-by-step explanation:

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16h - 9 = -13 - 6h - 18<br><br> h=
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Answer:

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Step-by-step explanation:

Solve for h:

16 h - 9 = -6 h - 31

Add 6 h to both sides:

16 h + 6 h - 9 = (6 h - 6 h) - 31

6 h - 6 h = 0:

16 h + 6 h - 9 = -31

16 h + 6 h = 22 h:

22 h - 9 = -31

Add 9 to both sides:

22 h + (9 - 9) = 9 - 31

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22 h = -22

Divide both sides of 22 h = -22 by 22:

(22 h)/22 = (-22)/22

22/22 = 1:

h = (-22)/22

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