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evablogger [386]
3 years ago
14

How many real and how many are imaginary Please Explain how to do it

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

There are no real solutions, and 2 imaginary solutions.

Step-by-step explanation:

There are no real solutions since the function never touches the x-axis and it does not have any roots. Imaginary solutions always come in pairs, and since the exponent degree of x is 2, there are 2 solutions to the problem. You can find the imaginary solutions by plugging the equation into the quadratic formula.

Doss [256]3 years ago
4 0

Answer:

no idea bud

Step-by-step explanation:

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Pls help it's an algebra question​
JulijaS [17]

Answer:

6 sided polygon or you cans say its called a hexagon

Step-by-step explanation:

Just divide, its not really an algebra answer, 34.08/5.68

3 0
3 years ago
What is the absoulte value of -1/4
____ [38]

\text{Hey there!}

\text{The absolute value of  a number basically is the size of a real number}\\\text{without regarding to its particular sign.}

\text{Now, that we have the (d)efinition of \bf{ absolute value}}\text{ we can answer}\\\text{ your question}

-\dfrac{1}{4}\mathsf{\  absolute\ value\ is: +\dfrac{1}4}}

\boxed{\boxed{\boxed{\mathsf{Thus,\ your\ answer\ is: \boxed{\boxed{\dfrac{1}{4}}}}}}}\checkmrak\checkmark

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7 0
3 years ago
Read 2 more answers
In exponential growth and decay problems, what is the independent variable? The independent variable is almost always: 
d1i1m1o1n [39]
The independent variable i<span>n exponential growth and decay problems is the time because the value of the given population will depend on the how much time have elapsed from the star of the decay or growth. in the usual form of a growth function is A(t) = Ao(e)^(kt)</span>
8 0
3 years ago
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Each bowling ball weighs 7.3*10^3 grams. The bowling alley has 2.0*10^2 bowling balls. How much do they all weigh, combined? Exp
Alexandra [31]

Answer:

1.46 x 10⁶g

Step-by-step explanation:

Given parameters:

Weight of each bowling ball  = 7.3 x 10³g

Number of balls in the bowling alley = 2.0 x 10²bowling balls

Unknown

The weight of the balls in the alley  = ?

Solution:

To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;

 Weight of the balls = 7.3 x 10³ x 2.0 x 10²

 Weight of the balls  = (7.3 x 2.0) x 10³⁺²

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3 0
3 years ago
Evaluate this expression
Yuki888 [10]

Answer:

B. -20.005

Step-by-step explanation:

( -86.005 ) + 66

= -20.005

8 0
3 years ago
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