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Nataly [62]
3 years ago
15

At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017

Mathematics
1 answer:
Anarel [89]3 years ago
4 0

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

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VLD [36.1K]
Unlikely as 1/3 is about 33.33% and it’s less than 50% so chances are not that great.
4 0
3 years ago
|25 POINTS| Suppose you have one pyramid with a base that is 10 meters long and 10 meters wide with a slant that is 15 meters. N
laiz [17]

Answer:

125 meters squared

Step-by-step explanation:

Surface area of initial pyramid:

  • A= 10²+4*1/2*10*15= 400 m²

Surface area of extended pyramid:

  • A= 10*15+2*1/2*15*15+2*1/2*10*15= 525 m²

The difference is:

  • 525- 400= 125 m²
3 0
3 years ago
Suppose that 10 years ago you bought a home for $160,000, paying 10% as a down payment, and financing the rest at 9% interest fo
Goshia [24]

Answer:

Current monthly payment on their existing mortgage would be $1158.66

Step-by-step explanation:

Total cash value = $160,000

Down payment = 10% of 160,000

Down Payment = $16,000

Balance amount = 160,000 - 16,000 = $144,000

Monthly payment formula:

P=\dfrac{r(PV)}{1-(1+r)^{-n}}

where,

PV is present value of home, PV=$144,000

r is rate per period , r=\frac{9}{1200}=0.0075

n is number of period, n=30x12 = 360

P=\dfrac{0.0075\times 144000}{1-(1+0.0075)^{-360}}

P=\$ 1158.66

Monthly payment would be same for 30 years.

Thus, Current monthly payment on their existing mortgage would be $1158.66

5 0
2 years ago
Let SSS represent the number of sunflower plants and LLL represent the number of lily plants Ezra's water supply can water.
Fantom [35]

Answer:

Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

Step-by-step explanation:

Given the inequality function

0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;

0.7S+0.5L≤11

0.7S+0.5(10)≤11

0.7S+5≤11

Taking 5 to the other side:

0.7S≤11-5

0.7S≤6

S≤6/0.7

S≤8.57

This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.

3 0
3 years ago
Fill in the table with relative frequencies by column.
Maslowich

Answer: determine the values to complete the relative frequency by row table... a=69.1 B=30.9 C=68.6 D=31.4

Explanation: I just did it and got it right hope it helps

3 0
2 years ago
Read 2 more answers
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