ILL GIVE BRAINLIEST TO WHOEVER SOLVES IN 10 MINSSolve each absolute value equation:

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

09909909 2345555333333333333333333333333333333333333333333333333333333

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Find the x intercept of the parabola with vertex 3,-2 and y intercept 0,7 round to the nearest hundredth

12345 [234]

An x-intercept is namely a "solution" or "zero" or "root" often called, and when that happens, y = 0, just like with any other x-intercept.

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\begin{cases}
h=3\\
k=-2
\end{cases}\implies y=a(x-3)^2-2
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=7
\end{cases}\implies 7=a(0-3)^2-2
\\\\\\
9=9a\implies \cfrac{9}{9}=a\implies 1=a\qquad therefore\qquad \boxed{y=(x-3)^2-2}$

so what is its x-intercept anyway?

$\bf \stackrel{y}{0}=(x-3)^2-2\implies 2=(x-3)^2\implies \pm\sqrt{2}=x-3
\\\\\\
\pm\sqrt{2}+3=x\qquad therefore\qquad (\pm\sqrt{2}+3~~~~,~~~~0)$

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lawyer [7]

Answer:

Step-by-step explanation:

Well You can tell right away its a positive line since its rising from left to right so the answer has to be positive

If the slope were to be 4 the line would be a Little more titleted becuasea slope of 4 is going up 4 and going tot he right 1.

ANd you can’t heck from any given point and just try all the positivw possibilties.

Or you can just use rise over run, start form a point, rise which means go up until you reach the second layer of the line and just run (go To The right) until you hit a point.

You’ll get 1/4

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