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RUDIKE [14]
3 years ago
12

A woman is 59 and one twelfth inches tall and her son is 57 and five ninths inches tall. How much taller is the woman​?

Mathematics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

1 and 19/36 inches

Step-by-step explanation:

All you have to do is subtract the woman's height by her son's height.

59 and 1/12 - 57 and 5/9 is 1 19/36

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Lines c and d are parallel lines cut by the transverse p which must be true by the corresponding angle theorem
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Pairs of corresponding angles are congruent.

 
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There were m visitors in an exhibition on the first day and 1,200 fewer vistors on the second day. On the third day, the number
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Answer:

Step-by-step explanation:

The average number is given by :

[m + (m - 1200) + (m - 1200)(1.30 ] / 3   =

[ 2m + 1.30m - 1200 - 1560] / 3   =

[3.3m - 2760] / 3  =

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3 years ago
2. A marketing firm is trying to estimate the proportion of potential car buyers that would consider
Maurinko [17]

Answer:

a. The number of people that should be in the pilot study are 600 people

b. The point estimate is 0.62\overline 6

c. At 95% confidence level the true population proportion of potential car buyers of hybrid vehicle is between the confidence interval (0.588, 0.6654)

d. Two ways to reduce the margin of error are;

1) Reduce the confidence interval

2) Use a larger sample size

Step-by-step explanation:

a. The given parameters for the estimation of sample size is given as follows;

The margin of error for the confidence interval, E = 4% = 0.04

The confidence level = 95%

The sample size formula for a proportion as obtained from an online source is given as follows;

n = \dfrac{Z^2 \times P \times (1 - P)}{E^2}

Where, P is the estimated proportions of the desired statistic, therefore, we have for a new study, P = 0.5;

Z = The level of confidence at 95% = 1.96

n + The sample size

Therefore, we have;

n = \dfrac{1.96^2 \times 0.5 \times (1 - 0.5)}{0.04^2} = 600.25

Therefore, the number of people that should be in the pilot study in order to meet this goal at 95% confidence level is n = 600 people

b. The point estimate for the population proportion is the sample proportion  given as follows;

\hat p = \dfrac{x}{n}

Where;

x = The number of the statistic in the sample

n = The sample size

From the question, we have;

The number of potential car buyers, n = 600

The number of respondent in the sample that indicated that they would consider purchasing a hybrid, x = 376

Therefore, the point estimate, for the proportion of potential car buyers that would consider buying a hybrid vehicle, \hat p = 376/600 = 0.62\overline 6

c. The confidence interval for a proportion is given as follows

CI=\hat{p}\pm z\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Therefore, we get;

CI=0.62 \overline 6\pm 1.96\times \sqrt{\dfrac{\hat{0.62 \overline 6}\cdot (1-\hat{0.62 \overline 6})}{600}}

C.I. ≈ 0.6267 ± 0.0387

The 95% confidence interval for the true population proportion of potential buyers of hybrid vehicle, C.I. =  (0.588, 0.6654)

d. The margin of error is given by the following formula;

MOE_\gamma = z_\gamma  \times \sqrt{\dfrac{\sigma ^2}{n} }

Where;

MOE_\gamma = Margin of error at a given level of confidence

z_\gamma = z-score

σ = The standard deviation

n = The sample size

Therefore, the margin error can be reduced by the following two ways;

1) Reducing the confidence interval and therefore, the z-score

2) Increasing the sample size

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Answer:

False

Step-by-step explanation:

Counterexample:

If i = 2, then the answer will be 16 and not 1.

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Answer:3

Step-by-step explanation:

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3 years ago
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