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Diano4ka-milaya [45]
3 years ago
8

There were m visitors in an exhibition on the first day and 1,200 fewer vistors on the second day. On the third day, the number

of vistors was 30% greator than the number of vistors on the second day. What was the average number of vistors over the three days?
Mathematics
1 answer:
STALIN [3.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

The average number is given by :

[m + (m - 1200) + (m - 1200)(1.30 ] / 3   =

[ 2m + 1.30m - 1200 - 1560] / 3   =

[3.3m - 2760] / 3  =

[1.1 m  - 920 ]

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Answer below

Step-by-step explanation:

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Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
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Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

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  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

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3 years ago
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Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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What is the area of this quadrilateral need help ASAP
vova2212 [387]

Answer:

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The figure is broken into different shapes so you find the area of each shape shown and add them up!

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