Ask question

Ask question

All categories

3 years ago

13

What is the slope of a line that is perpendicular to the line 2x-4y=24

1 answer:

DanielleElmas [232]3 years ago

3 0

Answer: y= -2x + 24

Step-by-step explanation

2x - 4y = 24

subtract 2x from both sides

divide 4y by 4y to get y by itself

then you get y= -2x + 24

You might be interested in

A trapezoid has a height of 10 centimeters. One parallel base has a length of 7 centimeters, and the other parallel base has a l

Papessa [141]

Answer:

I couldn't see the picture it is black

Step-by-step explanation:

the formula for the area of a trapezoid is:

$\frac{b1+b2}{2} h$

insert 7 for b1, 13 for b2, and 10 for h

$\frac{7+13}{2} 10$

100

Hope that helps

8 0

2 years ago

Please answer 25 points!

Alekssandra [29.7K]

Answer:

-3

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Find the value x2 when x = 5

Bumek [7]

Answer:

The value of x is 25

Step-by-step explanation:

x² when x = 5

So,

(5)² = 5 × 5 = 25

Thus, The value of x is 25

<u>-TheUnknownScientist</u><u> 72</u>

5 0

2 years ago

Read 2 more answers

This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out

Dmitry [639]

Base be y

ATQ

$\\ \sf\longmapsto xy=6050\dots 1$

$\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2$

Now

$\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy$

$\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2$

$\\ \sf\longmapsto 12100-12100=x^2+y^2$

$\\ \sf\longmapsto x^2+y^2=0\dots(3)$

From all equations

$\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy$

$\\ \sf\longmapsto (x-y)^2=0-2(6050)$

$\\ \sf\longmapsto (x-y)^2=-12100$

$\\ \sf\longmapsto (x-y)=110\dots(4)$

Now

Adding 3 and 4

$\\ \sf\longmapsto 2x=220$

$\\ \sf\longmapsto x=110m$

One side won't be covered hence

y=2(110)=220m

7 0

2 years ago

Read 2 more answers

Help with the first question!! Is it right??

Aloiza [94]

No its 20 u should know that

6 0

2 years ago