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Wittaler [7]
3 years ago
8

The value of 3 in 43158 is how many times the value of of 3 in 71435

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0
The 3 in 43158 is 1000* more than the 3 in 71435
prisoha [69]3 years ago
5 0
It is 100 because 30 x 100 =3,000
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Elina [12.6K]

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Step-by-step explanation:

 To solve this problem you must keep on mind the properties of logarithms:

log(b)-log(a)=log(\frac{b}{a})\\\\log(b)+log(a)=log(ba)\\\\a*log(b)=log(b)^a

Therefore, knowing the properties, you can write the expression gven in the problem as shown below:

5logx+6log(x+7)=logx^5+log(x+7)^6=logx^5(x+7)^6

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2 years ago
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nadya68 [22]

Step-by-step explanation:

The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.

{15x}^{2} (5x) =  {75x}^{3}   \\ 19x(5x)  = 95 {x}^{2} \\  6(5x)  = 30x

{15x}^{2} (3) = 45 {x}^{2}  \\ 19x(3) = 57x \\ 6(3) = 18

Combine like terms

{75x}^{3}  +  {95x}^{2}  +  {45x}^{2}  + 30x + 57x \\  + 18 = \\   {75x}^{3}  +  {140x}^{2}  + 87x + 18

The second one asks you to divide.

Factor out f(x):

{15x}^{2}  + 19x + 6

From dividing f(x) /g(x)

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To

\frac{(5x + 3)(3x + 2)}{5x + 3}

Cancel like terms since (5x+3) is on top and bottom of fraction.

You get 3x+2

5 0
3 years ago
Do these:<br> 1<br> 2<br> 3<br> 4<br> 5<br> 6<br> 7<br> 8<br> 9<br> 10
Elina [12.6K]

Answer:

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2. 99.3

4. 2.05

5. 14

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7. 28.531

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