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miv72 [106K]
3 years ago
6

Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Given:

Point is T(-3,8).

To find:

The coordinates of T' after R(y-axis)\circ R(x-axis).

Solution:

We know that, R(y-axis)\circ R(x-axis) means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

(x,y)\to (x,-y)

T(-3,8)\to T_1(-3,-8)

If a figure reflected across y-axis, then

(x,y)\to (-x,y)

T_1(-3,-8)\to T'(-(-3),-8)

T_1(-3,-8)\to T'(3,-8)

Therefore, the required point is T'(3,-8).

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Answer:

6a + 5a = 11

6a + 5a=

11a

11a = 11

divide both side by 11

11a/11 = 11/11

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B. The sum of three numbers is 51. The second number is three more than the first number, and the third number is
Svetach [21]

Answer:

12, 15, 24

Step-by-step explanation:

Let 1st # = x

Let 2nd # = x+3

Let 3rd # = 2x

Your equation is: x + (x+3) + 2x = 51

Add up all the x: x + x +3 +2x =51

Subtract 3 from both sides: 4x + 3 - 3 = 51 - 3

Divide 4 from both sides: 4x / 4 = 48 / 4

Your 1st number is x = 12

For the 2nd # it is 3 more than x so 12 + 3 = 15

For the 3rd # it is 2 times x so 2(12) = 24

Check your answers by adding up the numbers you solved: 12 + 15 +24 = 51

Does it equal to 51 as stated in the question? Yes, answers check out.

7 0
3 years ago
9. Determine how long it takes for 80% of the material to decay.
Vilka [71]

Using an exponential function, it is found that it takes 18.6 days for 80% of the material to decay.

The amount of a substance after t days is modeled by:

A(t) = A(0)e^{-kt}

In which:

  • k is the decay rate, as a decimal.
  • A(0) is the initial amount.

The half-life is of 8 days, hence A(8) = 0.5A(0), and this is used to find k.

A(t) = A(0)e^{-kt}

0.5A(0) = A(0)e^{-8k}

e^{-8k} = 0.5

\ln{e^{-8k}} = \ln{0.5}

-8k = \ln{0.5}

k = -\frac{\ln{0.5}}{8}

k = 0.08664339757

Hence:

A(t) = A(0)e^{-0.08664339757t}

The time it takes for 80% of the material to decay it t for which A(t) = 0.2A(0), hence:

0.2A(0) = A(0)e^{-0.08664339757t}

e^{-0.08664339757t} = 0.2

\ln{e^{-0.08664339757t}} = \ln{0.2}

-0.08664339757t = \ln{0.2}

t = -\frac{\ln{0.2}}{0.08664339757}

t = 18.6

It takes 18.6 days for 80% of the material to decay.

To learn more about exponential functions, you can take a look at brainly.com/question/24906920

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