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miv72 [106K]
3 years ago
6

Point T is at (-3, 8). What are the coordinates of T' after R(y-axis) o R(x-axis)?

Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

Given:

Point is T(-3,8).

To find:

The coordinates of T' after R(y-axis)\circ R(x-axis).

Solution:

We know that, R(y-axis)\circ R(x-axis) means the figure reflected across the x-axis then reflected across y-axis.

If a figure reflected across x-axis, then

(x,y)\to (x,-y)

T(-3,8)\to T_1(-3,-8)

If a figure reflected across y-axis, then

(x,y)\to (-x,y)

T_1(-3,-8)\to T'(-(-3),-8)

T_1(-3,-8)\to T'(3,-8)

Therefore, the required point is T'(3,-8).

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3 years ago
Explain why the function of f(x)=4x^2+8x is neither even or odd
myrzilka [38]

Answer:

By putting x = -x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

Step-by-step explanation:

We need to explain why the function of f(x)=4x^2+8x is neither even or odd

First we will understand, when the function is even and odd

Even function:

<em>A function is even if f(-x) = f(x) </em>

Odd function:

<em>A function is odd if f(-x) = -f(x) </em>

So, if we get the above result by putting x = -x, then we can say that the function is even or odd.

If we don't get any of the above results then the function is neither even nor odd.

So, for the given function: f(x)=4x^2+8x

Put x = -x

f(x)=4x^2+8x\\Put x=-x\\f(-x)=4(-x)^2+8(-x)\\f(-x)=4x^2-8x

So, by putting x=-x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

6 0
3 years ago
What is b for this question
kolezko [41]

Answer:

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Step-by-step explanation:

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3 years ago
SOLVE QUICK PLEASE!! 20 POINTS
PolarNik [594]

Answer:

SA = 384 in²

Step-by-step explanation:

Assuming we're finding surface area:

SA of top of large cube: 8(8) - 4(4) = 48 in²

SA of sides of large cube: 4(8)(8) = 256 in²

SA of exposed faces of small cube: 5(4)(4) = 80 in²

Total = 48 + 256 + 80 = 384 = ∑SA

6 0
3 years ago
HELP!!!<br> With working out... what’s the values of a b and c<br><br> (2x+1)(ax+b)=(6x^2-5x+c)
Lady bird [3.3K]

Answer:

Step-by-step explanation:

(2x + 1)(ax + b) = 6x² - 5x + c

Expand the left side and put that half into standard form:

2ax² + 2bx + ax + b = 6x² - 5x + c

2ax² + (2b + a)x + b = 6x² - 5x + c

So now look at the x terms. We have "2a" x² on left and 6 x² on right, so:

2a = 6

a = 3

Then look at the x terms, those coefficients will then be equal:

2b + a = -5

2b + 3 = -5

2b = -8

b = -4

and finally, then non-x terms are equal:

b = c

-4 = c

so:

a = 3, b = -4, c = -4

4 0
3 years ago
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