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likoan [24]
4 years ago
10

Paul's mp3 player has a total of 852 songs. He has 4 different groups of songs. If he puts an equal number of songs in each grou

p,how many songs will be in each group?
Mathematics
2 answers:
forsale [732]4 years ago
7 0

213 songs in each group.

Step-by-step explanation: you use hands on distributive property or partial quotients.

Igoryamba4 years ago
5 0

Answer:  

There will be 213 songs in each group.

Step-by-step explanation:

Suppose, the number of songs in each group is  x

As he has 4 different groups of songs, so the t<u>otal number of songs in all 4 groups</u> will be:  (4*x)= 4x

Given that, the mp3 player has a <u>total of 852 songs</u>. So, the equation will be........

4x=852\\ \\ x=\frac{852}{4}=213

So, there will be 213 songs in each group.

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The diagonal of the rectangle is 15 cm and one of its sides is 9 cm. find the area of the rectangle.
Tems11 [23]

The area of the rectangle is 108 square centimeters.

Given Information

The following information has been given in the question,

Length of the diagonal of the rectangle, l = 15 cm

Length of one of the sides of the rectangle, a = 9 cm

Let the other side of the rectangle be b.

Finding the Other Side of the Rectangle

According to Pythagoras Theorem,

(hypotenuse)² = (base)² + (perpendicular)²

Applying this theorem in the right-angle triangle formed by the diagonal and 9cm side of the rectangle, we get,

l² = a² + b²  [∵ The diagonal makes the hypotenuse]

(15)² = (9)² + b²

b² = (15)² - (9)²

b² = 225 - 81

b² = 144

b = √144

b = 12 cm

Calculating the Area of the Rectangle

Area of the rectangle, A = a × b

A = 9 × 12

A = 108 cm²

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5 0
2 years ago
What is x/9 = 9/27 help plz
Irina18 [472]
<h3><u>QUES</u><u>TION</u><u>:</u><u> </u></h3>

what is x/9 = 9/27 help plz

<h3><u>ANSWER</u><u> </u><u>AND</u><u> </u><u>SOLU</u><u>TION</u><u>:</u><u> </u></h3>

  • SOLVING FOR X

<u>Reduce</u><u> </u><u>first</u><u> </u><u>the</u><u> </u><u>fraction</u><u> </u><u>with</u><u> </u><u>9</u>

\large \sf  = \dfrac{x}{9}  =  \dfrac{ \cancel9}{ \cancel{27}}

<u>\large \sf =  \dfrac{x}{9}  =  \dfrac{1}{3}</u>

<u>Now</u><u> </u><u>simpli</u><u>fy</u><u> </u><u>using</u><u> </u><u>cross-multiply</u>

<u>\large \sf  = \dfrac{3x}{9}  = 1</u>

<u>\large \sf = 3x = 1 \times 9</u>

<u>\large \sf = 3x = 9</u>

<u>Lastly</u><u> </u><u>divide</u><u> </u><u>both</u><u> </u><u>sides</u>

<u>\large \sf = 3x \div 3 = 9 \div 3</u>

<u>\large \sf = x = 9  \div 3</u>

<u>\large \sf = x = 3</u>

<h3><u>FINAL</u><u> </u><u>ANSWER</u><u>:</u></h3>

\huge \orange{ \underline{ \boxed{ \sf{x = 3}}}}

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

7 0
3 years ago
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