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Korolek [52]
3 years ago
13

What is the equation of a line that is parallel to y=-3x+5 and passes through the point (5,-3).

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0
Your answer is y = -3x - 3

Hope it helped you on your question today : )
Harrizon [31]3 years ago
7 0
Y=-3x-3 is the correct equation that is parallel to your equation


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Given: AB=CD, BD=DE<br> Prove: AD=CE
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Write the expression as the sine, cosine, or tangent of an angle. sin 5x cos x - cos 5x sin x
mrs_skeptik [129]

Answer:

sin 5x cos x - cos 5x sin x = sin(4x)

Step-by-step explanation:

Given that the trigonometric expression,

sin 5x cos x - cos 5x sin x

Here we use the "sum and difference formulas"

Sum and Difference Formulas

sin(A+B)=sin A cos B + cos A sin B

sin(A-B)=sin A cos B - cos A sin B

cos(A+B)=cos A cos B - sin A sin B

cos(A-B)=cos A cos B + sin A sin B

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sin 5x cos x - cos 5x sin x = sin (5x - x)

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That's the final answer.

6 0
3 years ago
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Neporo4naja [7]

Answer:

B= 15 adults tickets

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x+y=50

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6 0
2 years ago
How do you write the difference of a number and eight, divided by ten
ch4aika [34]

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-------

7 0
3 years ago
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. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
3 years ago
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