Answer:5
Explaining:
10% of 50
= 10%=10/100 = 0.1
= 0.1 (x) times 50
= 5
<span>Mark the point of intersection between Circle eight in line A.B.</span>
Simplify the equation.
First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7
Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7
Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6
Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12
Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6
Hope this helps.
For this case we have the following equation:

Let 
We have:

By definition, given an equation of the form 
The quadratic formula, to find the solution can be written as:

In this case we have:

Substituting in the quadratic formula we have:
See attached image
Answer:
Option B
Answer:
Step-by-step explanation:
Given a function
, we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value "
" to another "
".
The rate of change of
between
and
can be calculated as follows:

For:

Let's find
and
, where:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

So:

And for:

Let's find
and
, where:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

So:

<em>Translation:</em>
Dada una función
, llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor "
" a otro "
".
La tasa de variación de
entre
y
, puede ser calculada de la siguiente forma:

Para:

Encontremos
y
, donde:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

Entonces:

Y para:

Encontremos
y
, donde:
![[x_1,x_2]=[-4,3]](https://tex.z-dn.net/?f=%5Bx_1%2Cx_2%5D%3D%5B-4%2C3%5D)

Entonces:
