A ↔ B ↔ C ↔ D ↔ E ↔ F
8 7 
???
AB + BC + CD = AD <em>segment addition postulate</em>
+ 8 + 7 = AD
+ 15 = AD
AD + 60 = 4AD
60 = 3AD
20 = AD
AB = = 
= 5
DE = 
= 
= 4
CD + DE + EF = CF <em>segment addition postulate</em>
7 + 4 + EF = CF
11 + EF = CF
Answer: 11 + EF
Note: You did not provide any info about EF. If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.
Answer:
It would be D because X^2 is different from 3x you would just multiply X^2 by 1 and 3x by 1 to get x^2+3x
I'm sorry I need the points lol anyways I hope you got the answer to it
Answer:
5029
Step-by-step explanation:
There is a common difference between consecutive terms, that is
d = - 201 - (- 215) = - 187 - (- 201) = - 173 - (- 187) = 14
This indicates the sequence is arithmetic with sum to n term
= [ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = - 215 and d = 14 , then
= [ (2 × - 215) + (46 × 14) ]
= 23.5 (- 430 + 644)
= 23.5 × 214
= 5029
Hold on i believe its C but let me go look on google and i'll get back to you to sure
