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rusak2 [61]
3 years ago
10

What is the slope of a line that passes through (���4,���13) and (19,11)?

Mathematics
2 answers:
zysi [14]3 years ago
7 0
I cant see the points. Theres just a bunch of question marks.
marin [14]3 years ago
6 0
-2/15.... Change in rise over run... (change in y over change in x)
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Which group of numbers is listed from least to greatest? -8, |-5|, -4, |3|, 6 |-6|, -4, |-2|, -1, 0 -4, |-2|, |3|, 5, |-7| -6, |
Anika [276]
I can’t help you because i can’t distinguish the groups
4 0
2 years ago
Help pls
stepladder [879]

Answer:

below

Step-by-step explanation:

therefore 2250 loaves where'nt sold

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2 years ago
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Please help please. I will mark brainlist
Alborosie

Answer:

I asked my teacher is she could help me and she said it was -7+10=3.       Step-by-step explanation:

6 0
2 years ago
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I need help I dont really get fractions lol. I will mark brainliest!
nevsk [136]
ANSWER:
7/8 and 6/8

7/8 remains the same

3/4 multiply the top and bottom by 2 so
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8 0
2 years ago
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HELP PLEASE ANYONE STEP BY STEP TIMED
UNO [17]

Answer:

\huge\boxed{\text{B) 4}}

Step-by-step explanation:

We can use the properties of some of these circles to solve and find the value of x.

FIrst off - we know that to find the side of a right triangle we can use the Pythagorean Theorem, which states that a^2 + b^2 = c^2 (a and b being legs, c being the hypotenuse.)

<h2><u>Finding the hypotenuse</u></h2>

We also know that this triangle is in a circle. Part of the hypotenuse and the altitude of the triangle are in the circle.

Point W is the center of the circle. Therefore, any points stretching to the edge from it will be equal (since this is a circle).

With this knowledge - UW and WZ are equal.

Therefore, since UW is x-1, WZ will be too.

We also know the length of VZ. We can add this to WZ to find the length of the whole hypotenuse.

\displaystyle x-1+2 \\ x+1

So the length of the hypotenuse, WV, is x+1.

<h2><u>Finding the value of x</u></h2>

Now that we know the length of the hypotenuse, we can use the Pythagorean Theorem like we stated before to find the value of x.

We know the two legs are x-1 and 2x-4, while the hypotenuse is

  • \displaystyle (x-1)^2 + (2x-4)^2 = (x+1)^2
  • (x^2 - 2x + 1) + (4x^2-16x+16) = (x^2 + 2x + 1) (use FOIL to find the value of each expression squared)
  • 5x^2 - 18x + 17 = x^2 + 2x + 1 (simplify the left side)
  • 4x^2 -20x + 16 = 0 (subtract both sides by x^2 +2x + 1)
  • x = \frac{{ -b \pm \sqrt {b^2 - 4ac} }}{{2a}} (Quadratic formula)
  • \frac{{ -(-20) \pm \sqrt {(-20)^2 - 4 \cdot 4 \cdot 16} }}{{2 \cdot 4}} (plug in values from equation)
  • \frac{{ 20 \pm \sqrt {400 - 256} }}{8}} (simplify)
  • \frac{{ 20 \pm \sqrt {144} }}{8}} (simplify)
  • \frac{{ 20 \pm 12 }}{8}} (simplify)
  • \displaystyle x = \frac{20+12}{8} \ \text{and} \ \frac{20-12}{8} (use plus/minus to find two roots)
  • \displaystyle x = \frac{32}{8} \ \text{and} \ \frac{8}{8} (simplify)
  • \displaystyle x = 4 \ \text{and} \ 1

1 can not be a possible answer because UW would end up being (1-1) = 0 units long! This isn't possible!

Therefore, the correct answer would be B) 4.

Hope this helped!

6 0
2 years ago
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