All categories

3 years ago

I don’t understand please help

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

start by going throught your answer choices...see if the segments listed are parallel...when you find an option that all the segments are parallel...you've got your answer

You might be interested in

4 Solve the system to find the y-value of the

ser-zykov [4K]

Answer: B

Step-by-step explanation:

7(-2) - 4(1) = -18

-14 - 4 = -18

-18 = -18

TRUE

(-2) + 12(1) = 10

-2 + 12 = 10

10 = 10

TRUE

3 0

2 years ago

Which phrase describes the algebraic expression x/15?

ss7ja [257]

The quotient of a number and 15

8 0

3 years ago

Read 2 more answers

12.3+9.75=?<br> 10,258÷46=?<br> Show your work

wariber [46]

Answer:

12.3 + 9.75 =22.05 10,258 ÷ 46 =

Step-by-step explanation:

for 10, 258 ÷ 46 i decide to type it

10258 46 = 223

223 = 2230 to the nearest tenth

223 = 223 to the nearest hundredth

223 = 223 to the nearest thousandth

= 0 to the nearest tenth

= 0 to the nearest hundredth

= 0 to the nearest thousandth

Other Divisions Math homework are

10258 divide by half plus 20

Homework answers: (10258/2) + 20 = 5149

10258 divide by half plus 40

Homework answers: (10258/2) + 40 = 5169

10258/46 divided by 2

Answer: (10258/46) ÷ 2 = 111.5

8 0

3 years ago

Let X1, X2, ... , Xn be a random sample from N(μ, σ2), where the mean θ = μ is such that −[infinity] < θ < [infinity] and

Sliva [168]

Answer:

$l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)$

And then the maximum occurs when $l'(\theta) = 0$ , and that is only satisfied if and only if:

$\hat \theta = \bar X$

Step-by-step explanation:

For this case we have a random sample $X_1 ,X_2,...,X_n$ where $X_i \sim N(\mu=\theta, \sigma)$ where $\sigma$ is fixed. And we want to show that the maximum likehood estimator for $\theta = \bar X$ .

The first step is obtain the probability distribution function for the random variable X. For this case each $X_i , i=1,...n$ have the following density function:

$f(x_i | \theta,\sigma^2) = \frac{1}{\sqrt{2\pi}\sigma} exp^{-\frac{(x-\theta)^2}{2\sigma^2}} , -\infty \leq x \leq \infty$

The likehood function is given by:

$L(\theta) = \prod_{i=1}^n f(x_i)$

Assuming independence between the random sample, and replacing the density function we have this:

$L(\theta) = (\frac{1}{\sqrt{2\pi \sigma^2}})^n exp (-\frac{1}{2\sigma^2} \sum_{i=1}^n (X_i-\theta)^2)$

Taking the natural log on btoh sides we got:

$l(\theta) = -\frac{n}{2} ln(\sqrt{2\pi\sigma^2}) - \frac{1}{2\sigma^2} \sum_{i=1}^n (X_i -\theta)^2$

Now if we take the derivate respect $\theta$ we will see this:

$l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)$

And then the maximum occurs when $l'(\theta) = 0$ , and that is only satisfied if and only if:

$\hat \theta = \bar X$

6 0

3 years ago

PLEASE HELP ME QUICKLY!<br> What is the product? (9×10^5)⋅(9×10^7)

OleMash [197]

8.1* 10^13 just the product or do you need it in scientific notation?

7 0

3 years ago

Read 2 more answers